Answer:
See below.
Step-by-step explanation:
7.)
Supplementary angles add up to 180°. ∠B's supplement is 22°. This means ∠B is 158°. Since ∠A ≅ ∠B, the m∠A = 158°.
8.)
Again, supplementary angles add up to 180°. ∠P is a right angle meaning it is 90°. Therefore, the m∠Q is 90° as well.
9.)
Complementary angles add up to 90°. In order for ∠S and ∠T to be complementary, they both need to angle measurements less than 90° meaning they both need to be acute angles.
Now that we know that ∠T is acute, the only way ∠U can be its supplement is if it has an angle measure greater than 90°. Therefore, ∠U is an obtuse angle.
10.)
Similar to question 9, if an angle is obtuse, its supplement must be an acute angle.
Answer:
Step-by-step explanation:
yes
Answer:
a) ![v(t) = 3t^{2} - 16t + 2](https://tex.z-dn.net/?f=v%28t%29%20%3D%203t%5E%7B2%7D%20-%2016t%20%2B%202)
b) The velocity after 3 seconds is -3m/s.
c)
and
.
Step-by-step explanation:
The position is given by the following equation.
![s(t) = t^{3} - 8t^{2} + 2t](https://tex.z-dn.net/?f=s%28t%29%20%3D%20t%5E%7B3%7D%20-%208t%5E%7B2%7D%20%2B%202t)
(a) Find the velocity at time t.
The velocity is the derivative of position. So:
.
(b) What is the velocity after 3 seconds?
This is v(3).
![v(t) = 3t^{2} - 16t + 2](https://tex.z-dn.net/?f=v%28t%29%20%3D%203t%5E%7B2%7D%20-%2016t%20%2B%202)
![v(3) = 3*(3)^{2} - 16*(3) + 2 = -19](https://tex.z-dn.net/?f=v%283%29%20%3D%203%2A%283%29%5E%7B2%7D%20-%2016%2A%283%29%20%2B%202%20%3D%20-19)
The velocity after 3 seconds is -3m/s.
(c) When is the particle at rest?
This is when
.
So:
![v(t) = 3t^{2} - 16t + 2](https://tex.z-dn.net/?f=v%28t%29%20%3D%203t%5E%7B2%7D%20-%2016t%20%2B%202)
![3t^{2} - 16t + 2 = 0](https://tex.z-dn.net/?f=3t%5E%7B2%7D%20-%2016t%20%2B%202%20%3D%200)
This is when
and
.
Answer:
-5x/125 is the correct answer