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fomenos
3 years ago
6

Two balls collide head-on on a table. The first ball has a mass of 0.50 kg and an initial velocity of 12.0 m/s. The second ball

has a mass of 0.75 kg and an initial velocity of -16.0 m/s. After the collision, the first ball travels at a velocity of -21.6 m/s. What is the velocity of the second ball after the collision? Assume a perfectly elastic collision and no friction between the balls and the table.
A. 6.4 m/s
B. 11.3 m/s
C. 17.8 m/s
D. 21.6 m/s
Physics
1 answer:
Gnom [1K]3 years ago
4 0
A is correct according to below calculation.
m₁v₀₁+m₂v₀₂=m₁v₁+m₂v₂
((m₁v₀₁+m₂v₀₂)-m₁v₁)/m₂=v₂
v₂=((.5*12-.75*16)+(.5*21.6))/.75
v₂=6.4 m/s
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Answer:

C) 20 m/s

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The velocity of a moving wave is

v = λf ............................ Equation 1

Where v = speed of the wave, λ = wave length, f = frequency of the wave.

Given: f = 2 Hz (two complete cycles in one seconds), λ = 10 meters

Substituting these values into equation 1

v = 2×10

v = 20 m/s.

Thus the speed of the wave = 20 m/s

The right option is C) 20 m/s

7 0
4 years ago
given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone brid
dalvyx [7]

Answer:

The balanced condition for Wheat stones bridge is  

Q

P

​  

=  

S

R

​  

 

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R  

1

​  

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R  

2

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=R+S

=20+30=50Ω

Net resistance of the network as R  

1

​  

 and R  

2

​  

 are in parallel

i=  

R

V

​  

=  

50

6×3

​  

=0.36 A.

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8 0
3 years ago
If a bus travel 200 km in 45 minutes calculate the speed in kilometre per minute​
erma4kov [3.2K]

Answer:

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6 0
3 years ago
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Question 6 (2 points)
LenKa [72]

Answer:

A. increase the speed

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3 0
3 years ago
A massless, rigid board is placed across two bathroom scales that are separated by a distance of 1.71 m. A person lies on the bo
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Answer:

Let the weight of the person be W and be located at a distance 'a' from the left scale as shown in the figure

Since the body is in equilibrium we can use equations of statics to analyse the problem.

Taking Sum of Moments about A we have

316\times 1.71-W\times a=0\\\\

Taking Sum of Moments about B we have

475\times 1.71-W\times (1.71-a)=0\\\\

Solving the above 2 equations for W and 'a' we get

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8 0
3 years ago
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