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Natalka [10]
3 years ago
6

Define upthrust simply (don't copy)​

Physics
1 answer:
EleoNora [17]3 years ago
3 0

Upthrust is the force that is pushing you up. Kinda to stop you from sinking right into the Earth. Upthrust is simply any force that is causing something to be pushed upwards. Kinda like the opposite of gravity, which is pulling you down =]

Hope this helps ❤️

You might be interested in
Select the correct answers.
diamong [38]

Answer:

decreases, increases, minimum (zero)

Explanation:

Kinetic energy of a body is directly proportional to the square of velocity of the body and the potential energy is directly proportional to the height  of the body at which it is placed.

The formula for the kinetic energy is

K = 1/2 m v^2

The formula for the potential energy is

U = m g  h

As the body goes up its kinetic energy decreases as the velocity of the object decreases.

As the body goes up the potential energy increases as the height increases.

At the top most point, the velocity of teh object is zero, so the kinetic energy at the top is zero.

8 0
3 years ago
Read 2 more answers
Which of these instruments is listed with the wrong type of lens that it uses?
VikaD [51]

The wrong type of lens-Microscope, concave

Explanation:

A microscope Basically  uses t<u>wo convex lenses to magnify an object, or specimen.</u>

There are  2 lenses in a microscope

  1. <u>Object Lens:</u>The lens that is closer to the object
  2. <u>Eyepiece:</u>The lens that is closer to the eye

Both the object lens and the  eyepiece, is a convex lens.

3 0
3 years ago
The biological roles of complex organic molecules are determined by their shape -- the way atoms and electrons create charge dis
Hatshy [7]

Answer:

a) P_α =  exp (-ΔE / kT),  b)   P_β = 0.145 , d)  ΔE = 309.7 meV

Explanation:

The expression for the number of molecules or particles in a given state in Boltzmann's expression

            n = n₀ exp (-ΔE / kT)

Where k is the Bolztmann constant and T the absolute temperature

The probability is defined as the number of molecules in a given state over the total number of particles

          P = n / n₀ = exp (- ΔE / kT)

Let's apply this expression to our case

a) P_α = n_α / n₀ = exp (-ΔE / kT)

b) the Boltzmann constant

       k = 1,381 10⁻²³ J / K (1 eV / 1.6 10⁻¹⁹ J) = 8.63 10⁻⁵ eV / K

       kT = 8.63 105 300 = 2,589 10⁻² eV

       P_β = exp (- 50 10⁻³ /2.589 10⁻² = exp (-1.931)

       P_β = 0.145

c) If the temperature approaches absolute zero, the so-called is very high, so there is no energy to reach the excited state, therefore or all the molecules go to the alpha state

d) For molecules to spend ¼ of the time in this beta there must be ¼ of molecules in this state since the decay is constant.

        P_β = ¼ = 0.25

     

       P_β = exp (- ΔE / kT)

       ΔE = -kT ln P_β

       ΔE = - 2,589 10⁻² ln 0.25

       ΔE = 0.3097 eV

       ΔE = 309.7 meV

3 0
3 years ago
Consider the elementary gas-phase reversible reaction A 3C Pure A enters at a temperature of 400 K and a pressure of 10 atm. At
xxMikexx [17]

Answer:

  • 39%

Explanation:

The equilibrium equation is:

          A\rightleftharpoons 3C

The initial concentration of A can be calculated from the ideal gas equation:

                 pV=nRT\\\\n/v=p/(RT)\\\\C_A=\dfrac{10atm}{0.08206(atm-dm^3/K-mol)/times 400K}\\\\C_A=0.304mol/liter

Determine the conversion of substance A to substance C using an ICE table and the Kc constant:

             A               ⇄          3C

I            0.304                        0

C             - x                          + 3x

E          0.304 - x                   3x

         K_c=0.25=\dfrac{(3x)^3}{(0.304-x)}

Solve for x:

You need to use a graphing calculator:

  • 108x³ = 0.304 - x
  • 108x³ + x - 0.304 = 0
  • x ≈ 0.1195 mol/liter

Then:

           C_A=0.304mol/liter-0.1195mol/liter=0.1845mol/liter\\\\C_C=3\times 0.304mol/liter=0.912mol/liter

The equilbrium conversion is:

           \% = [0.304mol/liter-0.1845mol/liter]/(0.304mol/liter)\times 100

           \% \approx 39\%

3 0
3 years ago
There is no( ) in time between the action and the reaction
Lesechka [4]
There is no (gap) in time between the action and the reaction

hope that helps:)
4 0
4 years ago
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