V=π * r^2 * h/3 = π * 2^2 * 8/3 ≈ 33.51032 or about 34 units^2
Answer:
<u>The system has two solutions:</u>
<u>x₁ = 5 ⇒ y₁ = -10</u>
<u>x₂ = -2 ⇒ y₂ = 11</u>
Step-by-step explanation:
Let's solve the system of equations, this way:
y = -3x + 5
y = x ² - 6x - 5
Replacing y in the 2nd equation:
y = x ² - 6x - 5
-3x + 5 = x ² - 6x - 5
x ² - 3x - 10 = 0
Solving for x, using the quadratic formula:
(3 +/- √(9 -4 * 1 * -10))/2 * 1
(3 +/- √9 + 40)/2
(3 +/- √49)/2
(3 +/- 7)/2
x₁ = 10/2 = 5
x₂ = -4/2 = -2
x₁ = 5 ⇒ y₁ = -10
x₂ = -2 ⇒ y₂ = 11
<u>As we can see the system has two different solutions</u>
<h3>
Answer: B) Only the first equation is an identity</h3>
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I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
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Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.
The amount needed to purchase materials needed to cover the area of the triangular flag is: $54.
<h3>What is the Area of a Triangle?</h3>
Area of a triangle = 1/2(bh)
Given the dimensions of the flag as the following:
base (b) = 18 in.
height (h) = √(41² - 9²) = 40 in.
Area of the flag = 1/2(18)(40) = 360 in.²
Cost of material needed = (360)(0.15) = $54
Learn more about area of a triangle on:
brainly.com/question/9030437
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