Physical properties are associated with physical changes.
For example: The physical properties of substances are as follows;
1. Melting
2. Freezing
3. Vaporization
Answer:
The skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
Explanation:
To solve the problem it is necessary to go back to the theory of conservation of momentum, specifically in relation to the collision of bodies. In this case both have different addresses, consideration that will be understood later.
By definition it is known that the conservation of the moment is given by:
Our values are given by,
As the skater 1 run in x direction, there is not component in Y direction. Then,
Skate 1:
Skate 2:
Then, if we applying the formula in X direction:
m_1v_{x1}+m_2v_{x2}=(m_1+m_2)v_{fx}
75*5.45-75*1.41=(75+75)v_{fx}
Re-arrange and solving for v_{fx}
v_{fx}=\frac{4.04}{2}
v_{fx}=2.02m/s
Now applying the formula in Y direction:
Therefore the skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
The answer is "the same than the mercury in the bigger tube".
If one barometer tube has twice the cross-sectional area of another, mercury in the smaller tube will rise the same than the mercury in the bigger tube.
The mercury will rise to the point where the column of mercury has the same weight as the force exerted by the atmosphere.
The force exerted by the atmosphere is pressure * cross-sectional area
Anf the weight of the column of mercury, W, will be:
W = m* g
where m = density * volume, and volume = cross-sectional area * height
=> W = density * cross-sectional area * height
Then, you make W = F and get:
density * cross-sectional area * height = P * cross-sectional area
The term cress-sectional area appears on both sides so it gets cancelled, and the height of the column of mercury does not depend on the cross-sectional area of the barometer.
Answer:
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Explanation:
