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anyanavicka [17]
3 years ago
10

An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater. The time de

lay of the echo to the ocean floor and back is 6 s. Show that the depth of the water directly below the vessel is 4590 m.
Physics
1 answer:
iragen [17]3 years ago
3 0

Explanation:

Given that,

An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater, v = 1530 m/s

The time delay of the echo to the ocean floor and back is 6 s, t = 6 s

The distance covered by the wave to reach its echo is 2d. The formula of speed is given by :

v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{1530\ m/s\times 6\ s}{2}\\\\d=4590\ m

So, the depth of the water directly below the vessel is 4590 m. Hence, proved.

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A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
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<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

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