Explanation:
Given that,
An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater, v = 1530 m/s
The time delay of the echo to the ocean floor and back is 6 s, t = 6 s
The distance covered by the wave to reach its echo is 2d. The formula of speed is given by :
So, the depth of the water directly below the vessel is 4590 m. Hence, proved.
Answer:
Explanation:
The speed of light is 3.0 x 10⁸ m/s
We need to find the distance traveled by it in one day.
1 day = 24 hours
1 day = 24 × 3600 seconds
= 86400 s
Now, using the formula of speed to find the distance covered as follows :
Putting all the values, we get :
Hence, light will cover of distance in one day.
Answer:
a) the one with a lower orbit b) the one with a higher orbit
Explanation:
Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.
In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.
.
so the velocity is
where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.
The orbital period of any object in orbit is
where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.