Answer:
23.63 °C
Explanation:
= mass of water = 0.250 kg
= initial temperature of water = 20.0 °C
= Specific heat of water = 4186 J/(kg °C)
= mass of aluminum = 0.400 kg
= initial temperature of aluminum = 26.0 °C
= Specific heat of aluminum = 900 J/(kg °C)
= mass of copper = 0.100 kg
= initial temperature of copper = 100 °C
= Specific heat of copper = 386 J/(kg °C)
= Final temperature of mixture
Using conservation of heat
( - ) + ( - ) + ( - ) = 0
(0.250) (4186) ( - 20) + (0.400) (900) ( - 26) + (0.100) (386) ( - 100) = 0
= 23.63 °C