Question

An ideal gas undergoes an adiabatic process and does 25 joules of work on its environment. What is the change in internal energy? a.50 joules b. 25 joules c. 0 joules d. -25 joules

Answer 1

Using Δh = q+w
under adiabatic conditions q = 0
w= 25joules
Δh= 25joules

Answer 2

Answer:

The change in internal energy will be 25 J.

Explanation:

Given that,

Work done = 25 J

Using first law of thermodynamics

The internal energy is sum of the heat and work done.

$\Delta U= Q+ W$

Where, $\Delta U$ = Change in internal energy

Q =  heat

W = work done

In adiabatic process, the heat does not change, it remains constant.

So the heat Q = 0

Therefore, The change in internal energy will be

$\Delta U=0+25 J$

$\Delta U= 25 J$

Hence, The change in internal energy will be 25 J.