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MAVERICK [17]
3 years ago
12

What is 6.24x10^-4 in regular numbers

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

0.000624

Explanation:

Since your exponent has a negative sign, the number will get smaller.  The decimal point will move to the left as 4 places.

0.624

0.0624

0.00624

0.000624

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You have a mixture of the gases Cl₂ and O₂ along with some N₂ in a container at STP. The moles of Cl₂ and O₂ in the mixture are
Harman [31]

The mole fraction of N₂ in the mixture, given the data is 0.225

<h3>How to determine the mass of the mixture</h3>
  • Density of mixture = 2.063 g/L
  • Volume (at STP) = 22.4 L
  • Mass of mixture =?

Density = mass / volume

Cross multiply

Mass = Density × volume

Mass of mixture = 2.063 × 22.4

Mass of mixture = 46.2112 g

<h3>How to determine the mole fraction of N₂</h3>

We'll begin by calculating the mole of N₂ in the mixture. This can be obtained as follow:

  • Mass of mixture = 46.2112 g
  • Let the mole of Cl₂ = y
  • Let the mole of O₂ = Mole of Cl₂ = y
  • Total mole = 1 mole
  • Let the mole of N₂ = x =?

Total mole = Mole of N₂ + Mole of Cl₂ + Mole of O₂

1 = x + y + y

1 = x + 2y

2y = 1 - x

y = (1 - x) / 2

Mass of mixture = mass of N₂ + mass of Cl₂ + mass of O₂

Recall

mass = mole × molar mass

Thus,

Mass of mixture = (mole of N₂ × molar mass) + (mole of Cl₂ × molar mass) + (mole of O₂ × molar mass)

46.2112 = 28x + 71y + 32y

But

y = (1 - x) / 2

46.2112 = 28x + 71(1 - x) / 2 + 32(1 - x) / 2

Multiply through by 2

92.4224 = 56x + 71(1 - x) + 32(1 - x)

92.4224 = 56x + 71 - 71x + 32 - 32x

Collect like terms

92.4224 - 71 - 32 = 56x - 71x - 32x

-10.5776 = -47x

Divide both sides by -47

x = -10.5776 / -47

x = 0.225 mole

Finally, we can determine the mole fraction of N₂. This can be obtained as follow:

  • Mole of N₂ = x = 0.225 mole
  • Total mole = 1 mole
  • Mole fraction of N₂ = ?

Mole fraction = mole / total mole

Mole fraction of N₂ = 0.225 / 1

Mole fraction of N₂ = 0.225

Learn more about mole fraction:

brainly.com/question/2769009

#SPJ1

8 0
1 year ago
If the melted lead got hot enough to vaporize, how much energy would it have taken to vaporize 21
arsen [322]

Answer:

18 KJ

Explanation:

Data Given:

mass of Lead (m) = 21 g

Heat taken for vaporization (Q) = ?

Solution:

This problem is related to phase change and latent heat of vaporization.

Latent heat of vaporization is the amount of heat taken to convert one mole of substance at its boiling point to its vapor.

So, Latent heat of vaporization of lead has a constant value

Latent heat of vaporization of lead = 177.7 KJ/mol

Formula used

Q = m x Lv. . . . . (1)

where

Lv = specific latent heat of vaporization

here the value for latent heat of vaporization is for mole so instead of mass we will use moles in formula.

So,

Q = no. of mol x Lv. . . . . (2)

first find no. of moles for 21 g of lead

                  no. of moles = mass in grams / molar mass . . . . . . (3)

molar mass of  lead (Pb) = 207 g/mol

put values in equation 3

                      no. of moles = 21g / 207 g/mol

                      no. of moles = 0.101 mol

so,

number of moles of lead (Pb) = 0.101 mol

Put values in the eq.2

                      Q = 0.101 mol x 177.7 KJ/mol

                      Q = 18 kJ

So, 18KJ of heat is taken to vaporize 21 g of lead (Pb)

5 0
3 years ago
Similar
victus00 [196]

Answer:

-Acetone is a covalent compound, while sodium chloride is an ionic compound

-covalent compounds have weak attractions between molecules, resulting in low melting points

Explanation:

3 0
3 years ago
Read 2 more answers
Find the boiling point?<br> 100. g of C2H6O2 dissolved in 200 g of H2O?
aleksklad [387]

Answer:

The correct answer is 104.13ºC

Explanation:

When a solute is added to a solvent, the boiling point of the solvent (Tb) increases. That is a colligative property. The increment in Tb (ΔTb)  is given by the following expression:

ΔTb = Tb - Tbº= Kb x m

Where Tb and Tbº are the boiling points of the solvent in solution and pure, respectively; Kb is a constant and m is the molality of the solution.

In this problem, the solvent is water (H₂O). It is well known that water has a boiling point of 100ºC (Tb). The value of Kb for water is 0.512ºC/m. So, we have to calculate the molality of the solution (m):

m = moles of solute/Kg solvent

The solute is C₂H₆O₂ and we have to calculate the number of moles of this component by dividing the mass into the molecular weight (Mw):

Mw(C₂H₆O₂)= (2 x 12 g/mol) + (6 x 1 g/mol) + (2 x 16 g/mol)= 62 g/mol

⇒ moles of C₂H₆O₂ = mass/Mw = 100 g/(62 g/mol) = 1.613 moles

Now, we need the mass of solvent (H₂O) in kilograms, so we divide the grams into 1000:

200 g x 1 kg/1000 g = 0.2 kg

Finally, we calculate the molality as follows:

m = 1.613 moles of C₂H₆O₂/0.2 kg = 8.06 moles/kg = 8.06 m

The increment in the boiling point will be:

ΔTb = Kb x m = 0.512ºC/m x 8.06 m = 4.13ºC

So, the boiling point of pure water (Tbº=100ºC) will increase in 4.13ºC:

Tb= 100ºC+4.12ºC= 104.13ºC

5 0
3 years ago
On the ph scale, indicate which direction is increasingly acidic and which is increasingly basic.
alexdok [17]
1 2 3 4 5 6 7 8 9 10 11 12 13 14
From 1-6.5 ph acidic
From 7-14 ph alkaline
8 0
3 years ago
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