Which table of values will generate this graph?

Solve 4(-4x- 3)> 36

wariber [46]

Answer:

x=3

Step-by-step explanation:

Simplifying

4(4x + -3) = 36

Reorder the terms:

4(-3 + 4x) = 36

(-3 * 4 + 4x * 4) = 36

(-12 + 16x) = 36

Solving

-12 + 16x = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.

-12 + 12 + 16x = 36 + 12

Combine like terms: -12 + 12 = 0

0 + 16x = 36 + 12

16x = 36 + 12

Combine like terms: 36 + 12 = 48

16x = 48

Divide each side by '16'.

x = 3

Simplifying

x = 3

8 0

3 years ago

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Roxanne graphed this system of equations to find the solution.

Mice21 [21]

Answer:

Option C is correct.

She is not correct as she use the wrong y intercepts when graphing the equations.

Step-by-step explanation:

Given the system of equations:

$y = \frac{2}{3}x-5$ .....[1]

$y = -2x+3$ . .....[2]

equate these two equations we get;

$\frac{2}{3}x-5=-2x+3$

Add 5 to both sides we get;

$\frac{2}{3}x = -2x+8$

Add 2x to both sides we have;

$\frac{8}{3}x = 8$

Multiply both sides by 3 we get;

8x = 24

Divide both sides by 8 we get;

x = 3

Substitute the value of x in [2] we have;

y = -2(3)+3 = -6+3

Simplify:

y = -3

Therefore, the correct solution for this given system of equation is (3, -3)

You can see the graph of these equations below.

5 0

3 years ago

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There are 7 acts in a talent show.

lara31 [8.8K]

Answer:

Event A: 1/35

Event B: 1/840

Explanation:

Event A

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first four acts can be scheduled is:

$C(m,n)=\dfrac{m!}{n!(m-n)!}$

$C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35$

And the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order, is 1: C(4,4).

Therefore the probability of Event A is:

$P(A)=1/35$

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which four acts can be scheculed when the order matters is:

$P(m,n)=\dfrac{m!}{(m-n)!}$

$P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840$

The number of ways the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth is 1: P(4,4)

Therefore, the probability of Event B is:

$P(B)=1/840$

7 0

3 years ago

Find the average rate of change for the given function from x = −1 to x = 2.

Mashutka [201]

$the \: average \: rate \: of \: change = \frac{f(x2) - f(x1)}{x2 - x1} \\ \frac{f(2) - f( - 1)}{ 2 - - 1} = \\ \frac{ - 3(2) + 2 - ( - 3( - 1) + 2)}{3} = \\ \frac{ - 6 + 2 - 3 - 2}{3} = \frac{ - 9}{3} = - 3$

3 0

2 years ago

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Please help me with this

Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

$\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}$

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

$\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }$

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

$\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }$

Thefore the required answer is ,

$\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}$

4 0

2 years ago

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