Answer: The answer is 72
Step-by-step explanation:
Answer:C
Step-by-step explanation:
Answer:
Step-by-step explanation:

Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
Answer:
10
Step-by-step explanation:
Firstly, AM=x+8
or, A=x+8-M......eqn (i)
MB=6x-2
or, B=6x-2-M......eqn (ii)
Now,
from eqn (i) and (ii)
x+8-M=6x-2-M
or, 8+2=6x-x-M+M
or, 10=5x
or, 10÷5=x
therefore, x=2
Again,
MB=6x-2
=6×2-2
=12-2
=10
is it correct
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