BRAINLIEST, THANKS AND 5 STARS IF ANSWERED BOTH CORRECTLY

Mathematics

2 answers:

ratelena [41]3 years ago

6 0

Answer:

Numer 1

A) (-5, -4), (-4, -3), (-3, -2), (-2, -1) Is a function

Number 2

C) (-5, -1), (-2, -1), (1, -1), (4, -1) is a function

olga2289 [7]3 years ago

4 0

in a function, all elements in domain "x" should have a pre-image "y" and they should be unique (one x can have only one value of y, but more than one x can have same same value of y) for all ordered pair (x,y)

it's not clearly possible to tell without knowing the actual set but with given information,

1. A

2. C

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Find the value of the constant term in the expansion of x^4 (x+3/2x^2)^5

Nataly_w [17]

5 is the answer ok I'll explain

4 0

3 years ago

Which expression is a fourth root of -1+isqrt3?

aleksklad [387]

Answer:

Step-by-step explanation:

$\sf n^{th}$ roots of a complex number is given by DeMoivre's formula.

$\sf \boxed{\bf r^{\frac{1}{n}}\left[Cos \dfrac{\theta + 2\pi k}{n}+i \ Sin \ \dfrac{\theta+2\pi k}{n}\right]}$

Here, k lies between 0 and (n -1) ; n is the exponent.

$\sf -1 + i\sqrt{3}$

a = -1 and b = √3

$\sf \boxed{r=\sqrt{a^2+b^2}} \ and \ \boxed{\theta = Tan^{-1} \ \dfrac{b}{a}}$

$\sf r = \sqrt{(-1)^2 + 3^2}\\\\ = \sqrt{1+9}\\\\=\sqrt{10}$

$\sf \theta = tan^{-1} \ \dfrac{\sqrt{3}}{-1}\\\\ = tan^{-1} \ (-\sqrt{3})$

$\sf = \dfrac{-\pi }{3}$

n = 4

For k = 0,

$\sf z = \sqrt[4]{10}\left[Cos \ \dfrac{\dfrac{-\pi}{3} +0}{4}+iSin \ \dfrac{\dfrac{-\pi}{3}+0}{4}\right] \\\\\\z= \sqrt[4]{10} \left[Cos \ \dfrac{ -\pi }{12}+iSin \ \dfrac{-\pi}{12}\right]\\\\\\z = \sqrt[4]{10}\left[-Cos \ \dfrac{\pi}{12}-i \ Sin \ \dfrac{\pi}{12}\right]$