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Masteriza [31]
3 years ago
10

How many moles of water molecules are found in 3.80 moles of zinc(ii) sulfate heptahydrate?

Chemistry
1 answer:
Sindrei [870]3 years ago
3 0
Zinc (ii) sulfate heptahydrate has a formula of ZnSO4.7H2O 
Therefore, note that one mole of ZnSO4.7H2O, contains 7 moles of H2O,
Hence, 3.8 moles of ZnSO4.7H2O will contain;
   3.8 × 7/1
  = 26.6 moles of H2O
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¿Cuál es el % m/m de una disolución en que hay disueltos 22 g de soluto en 44 g de disolvente?
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The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?

Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

Explanation:

Given: Mass of solute = 22 g

Mass of solvent = 44 g

The percentage m/m is calculated using the following formula.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100

Substitute the values into above formula as follows.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{22 g}{44 g} \times 100\\= 50 percent

Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

5 0
2 years ago
How many atoms of gold are in a pure gold coin weighing 12.0g?
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<span>So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).
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0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23 

<span>Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 </span>

<span>That should be your answer!

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3 years ago
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Answer:

Explanation:

True

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