All categories

3 years ago

Calculate the molarity of 0.850 mol of Na2S in 1.70 L of solution.

1 answer:

5 0

Molarity is simply the ratio of the number of moles of a substance over the total volume of the solution. Assuming that the addition of 0.850 moles does not change the overall volume of 1.70 L, therefore molarity is simply:

Molarity = 0.850 moles / 1.70 L = 0.5 moles / L = 0.5 M

You might be interested in

The process of breaking down Glucose and using the energy stored in that molecule for cellular function is known as_____.

Katyanochek1 [597]

Answer:

Cellular respiration.

Explanation:

Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.

3 0

3 years ago

Which is unique to the tire of the car

kvasek [131]

it is c trench marks

7 0

3 years ago

Read 2 more answers

Using only the periodic table, rank the elements in each set in order of increasing size: (a) Se, Br, Cl; (b) I, Xe, Ba.

mezya [45]

Answer:

A. Cl, Se, Br

B. I, Xe, Ba

Explanation:

4 0

3 years ago

A student heats 10.52 g of sodium hydrogen carbonate in a crucible until the compound completely decomposes to sodium carbonate

saveliy_v [14]

Answer:

$m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3$

Explanation:

Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

$2NaHCO_3(s)\rightarrow Na_2CO_3(s)+H_2O(g)+CO_2(g)$

Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

$m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3} *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3$

Best regards!

4 0

2 years ago

What is kinetic energy? *

finlep [7]

Answer:

energy which a body possesses by virtue of being in motion

Explanation:

the work needed ro accelerate a body of given mass

4 0

2 years ago