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3 years ago

AL

Chemistry

1 answer:

Helga [31]3 years ago

4 0

Metallic I’m pretty sure. :)

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Explain why we must balance all chemical equations

enyata [817]

Answer:

The chemical equation needs to be balanced so that it follows the law of conservation of mass.

Explanation:

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3 years ago

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An individual with the disorder Xeroderma pigmentosum is hypersensitive to sunlight succumbs to DNA damage caused by light expos

olya-2409 [2.1K]

This disorder is inherited through DNA because there is a lack of pigmentation in the skin.

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3 years ago

If there are 5 protons, how many electrons does the atom have?

Tresset [83]

If this is a single atom of Boron, there should be 5 electrons as well. Boron as an electron configuration of 2-3 or 1s2 2s2 2p

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3 years ago

Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop

Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

Mg + Cu(NO₃)₂ ⇒ Mg(NO₃)₂ + Cu

Reactants Elements Products

1 Mg 1

1 Cu 1

2 N 2

6 O 6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

= 24 + 28 + 96

= 148 g

24 g of Mg -------------------- 148 g of Mg(NO₃)₂

147.4 g of Mg ------------------- x

x = (147.4 x 148) / 24

x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = $\frac{actual yield}{theoretical yield}$

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = $\frac{30.8}{100}$ x 908.96

Actual yield = 279.95 ≈ 280g

4 0

3 years ago

For the simple decomposition reaction AB(g) → A(g) + B(g) rate = k[AB]2 and k = 0.20 L/mol·s. If the initial concentration of AB

Pepsi [2]

Answer:

[AB] = 0.66M

Explanation:

rate = change in concentration/time

Initial concentration of AB = 1.5M

Let the concentration of AB after 10.3s be y

Therefore, rate = 1.5 - y/10.3

The rate equation is given as

rate = k[AB]^2 = 0.2y^2

0.2y^2 = 1.5 - y/10.3

2.06y^2 = 1.5 - y

2.06y^2 + y - 1.5 = 0

Using the quadratic formula

y = [-1 + or - √(1^2 -4×2.06×-1.5)/2(2.06)]

The value of y must be positive

y = (-1 + √13.36)/4.06 = -1+3.66/4.06 = 2.66/4.06 = 0.66

Concentration of AB after 10.3s is 0.66M

5 0

3 years ago