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Arlecino [84]
3 years ago
12

Candy selling at $6.00 per pound will be mixed with candy selling at $9.00 per pound. How many pounds of the more expensive cand

y are needed to produce a 15-pound mixture that sells for $7.00 per pound?
Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0
Let us call X the number of pounds of $6 candies and Y the number of pounds of $9 candies.
We know that:
X+Y=15 (we are picking a total of 15 pounds)
(6X+9Y)/15=7 (the average of each pound out of those 15 is "valued" $7)

So you can deduce that Y=15-X
Then replace Y in the other equation by 15-X which is:
(6X+9*(15-X))/15=7
(6X+135-9X)/15=7
(135-3X)/15=7
135-3X=7*15
135-3X=105
-3X=-30
X=10

So you can deduce that Y=15-10=5

As a matter of fact you can verify that 10 pounds of the first candies are valued $60 and 5 pounds of the seconds are valued $45 which is a total of 105.
105/15=7 which means that the overall 15 pounds do have an average per-pound-value of $7.
shutvik [7]3 years ago
8 0

Answer:

10

Step-by-step explanation:

look at the answer above for explanation

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one angle has a measure that is less than 15 than two times a number. a second angle is three times the number. the angles are c
adell [148]

Answer:

27 degrees and 63 degrees

Step-by-step explanation:

Let n be the number.

Angle 1: 2n-15

Angle 2: 3n

If the angles are complementary they add up to 90.

Therefore we can write an equation.

2n-15+3n=90

Combine like terms

5n-15=90

Add 15 to both sides

5n=105

n=21

Now we plug 21 in for n and solve for the angles

Angle 1 = 2(21)-15

Angle 1 = 42-15

Angle 1 = 27

Angle 2 = 3(21)

Angle 2 = 63

4 0
2 years ago
What 3 numbers multiply to get 63?
masya89 [10]
There are many combinations if the numbers are not required to be integers.

If they are required to be integers, I'd suggest:

3*7*3 = 63
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