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Arlecino [84]
3 years ago
12

Candy selling at $6.00 per pound will be mixed with candy selling at $9.00 per pound. How many pounds of the more expensive cand

y are needed to produce a 15-pound mixture that sells for $7.00 per pound?
Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0
Let us call X the number of pounds of $6 candies and Y the number of pounds of $9 candies.
We know that:
X+Y=15 (we are picking a total of 15 pounds)
(6X+9Y)/15=7 (the average of each pound out of those 15 is "valued" $7)

So you can deduce that Y=15-X
Then replace Y in the other equation by 15-X which is:
(6X+9*(15-X))/15=7
(6X+135-9X)/15=7
(135-3X)/15=7
135-3X=7*15
135-3X=105
-3X=-30
X=10

So you can deduce that Y=15-10=5

As a matter of fact you can verify that 10 pounds of the first candies are valued $60 and 5 pounds of the seconds are valued $45 which is a total of 105.
105/15=7 which means that the overall 15 pounds do have an average per-pound-value of $7.
shutvik [7]3 years ago
8 0

Answer:

10

Step-by-step explanation:

look at the answer above for explanation

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Step-by-step explanation:

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a small business averages 5,500$ per month in online revenue plus another 300$ per salesperson per month. which graph shows all
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Someone please help me I’ll give out brainliest please dont answer if you don’t know
Katena32 [7]

Answer:

x≥−3

Step-by-step explanation:

Let's solve your inequality step-by-step.

2x+3/ −3 ≤1

Step 1: Simplify both sides of the inequality.

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Step 2: Add 1 to both sides.

−2/ 3 x−1+1≤1+1

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Step 3: Multiply both sides by 3/(-2).

( 3/ −2 )*( −2/ 3 x)≤( 3/ −2 )*(2)

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Answer:

x≥−3

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