For 3 days....
option 1 : 25(3) + 0.10m = 75 + 0.10m
option 2 : 60(3) = 180
180 < 75 + 0.10m
180 - 75 < 0.10m
105 < 0.10m
105 / 0.10 < m
1050 < m.....this is minutes, we need hrs
1050/60 < m
17.5 < m.......the guest would have to spend more then 17.5 hrs
Considering that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, it is found that it is significant at the 5% level, but not at the 1% level.
<h3>When a measure is significant?</h3>
- If p-value > significance level, the measure is not significant.
- If p-value < significance level, the measure is significant.
Using a z-distribution calculator, it is found that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, hence, this is significant at the 5% level, but not at the 1% level.
More can be learned about p-values at brainly.com/question/16313918
Answer:
All you have to do is find the rest of the percentage. Percentage adds up to 100%. So you will have to add the two percentages they gave you. 27+33=60%. Now you have to take away 60 from 100. 100-60=40%.
40%- That's the answer.
Hope this helps.
Answer:
5
Step-by-step explanation:
60÷6 is 10
54÷6 is 9
30÷6 is 5
Answer:
98 x 24 = 2352
2352 x 2400 = 5,644,800
2352 x (-48) = - 112,896
5,644,800 - 112,896 = 5,531,904
5,531,904 x 24 = 132,765,696
Step-by-step explanation:
