Ask question

Ask question

All categories

3 years ago

5

A climber who is 6 feet tall, casts a shadow that is 20 feet tall, at the same time that a tree casts a shadow which is 90 feet

long. How tall is the tree? (Type your answer as a whole number followed by the unit abbreviation, like this example: 12 ft.)

2 answers:

Agata [3.3K]3 years ago

8 0

The tree is about 27.3 ft. tall.

Trava [24]3 years ago

6 0

27. Ft. hopes this helps

You might be interested in

A school survey reported that 16.% of the students in Zed's homeroom class ride their bikes to school. This percent represents a

Lilit [14]

Answer:

16 3/5

Step-by-step explanation:

thank divinesworldtv they have the right answer

7 0

3 years ago

Part A: Victor is studying for his Finais. He spends 1/3 of an hour studying for History, 2/3 an hour

Elan Coil [88]

Answer:

3 3/4

Step-by-step explanation: all that you have to do is add 1/3 +2/3+11/4 which gives you 3 3/4

4 0

3 years ago

When you find 36 is 42% of what number, what are you looking for?

arsen [322]

Answer:

dezzzz nuts

Step-by-step explanation:

im eating poop

5 0

3 years ago

Solve the unknown variable

dsp73

Set measurements equal to each other.
7X + 20 = 8X + 8
-7X -7X

20 = X + 8
-8 -8

ANSWER: X=12

5 0

3 years ago

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago