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Vlada [557]
3 years ago
9

Please help me! Given (x+a)(x+b) = x^2+x-12, what is the value of a^2+b^2

Mathematics
1 answer:
Sonja [21]3 years ago
4 0
(x + 4) (x - 3)
a = 4
b = -3

a^2 + b^2 = ...
= 4^2 + (-3)^2
= 16 + 9
= 25
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If a dozen eggs cost $1.35, what is the unit cost?
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Determine if Ginny factored correctly. If not, explain where she made an error. Ginny made a mistake in step 1 when she identifi
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Quadratic equations are second-order equations. Ginney made a mistake when she identified b = 31. It should be b = –31.

<h3>What is a Quadratic Equation?</h3>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

In order to find the mistake that Ginny made, we will first find the factors ourselves, therefore, we will factorize the trinomial,

6x^2 - 31x -30 = 0

As we can see that the value of constants are,

a = 6

b = -31

c = 30

6x^2 - 31x -30 = 0\\\\6x^2 - 36x+5x -30 = 0\\\\6x(x-6)+5(x-6)=0\\\\(6x+5)(x-6)=0

Therefore, the factors of the trinomial 6x^2 - 31x -30 = 0 are (6x+5) and (x-6).

If we compare our process with Ginny's process, we will find that she has taken the value of the constant b as 31 which is wrong.

Hence, Ginney made a mistake when she identified b = 31. It should be b = –31.

Learn more about Quadratic Equation:

brainly.com/question/17177510

3 0
3 years ago
Read 2 more answers
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