Quiz due in 45 minutes, will up the points and MARK BRAINLIEST please solve this.

O 1) Which below graph represents direct variation? GRAPH A or GRAPH B Why?

Zina [86]

Answer:

Graph B

Step-by-step explanation:

The equation for direct variation is y=kx, with k being the slope. As you can see from the equation, there is no y-intercept. In graph A, you would add 8; therefore, it does not meet the requirements for direct variation.

4 0

2 years ago

I don’t know what to do

n200080 [17]

Answer:

x = 7

y = 12

Step-by-step explanation:

To do this question you have to know your exponent rules, but also you need to know how to add fractions.

To multiply

6^(1/3) × 6^(1/4)

you can keep the 6 and just add the exponents.

That's why the answer is set up on the form 6^(x/y)

To add fractions, you need a common denominator, it is 12.

1/3 is 4/12.

1/4 is 3/12.

So 1/3 + 1/4

is the same as:

4/12 + 3/12

= 7/12

7/12 is the exponent you are looking for.

x = 7 and y = 12.

6^(1/3) × 6^(1/4)

=6^(7/12)

4 0

2 years ago

Which of the following best describes perpendicular lines

Usimov [2.4K]

Answer:

B.

Step-by-step explanation:

Perpendicular lines always intercept at a right angle (90 degrees).

8 0

3 years ago

Read 2 more answers

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

Jimmy works part-time at Walmart earning $11 per hour. He is allowed to work anywhere between 0 to 30 hours per week. His only e

Mashcka [7]

The answer is letter A.

8 0

3 years ago