Answer:
Is this pure maths cause I don't know what's going on here
Answer:
Step-by-step explanation:
Given is a function as 
Equating to 0 we have equation
If the function f(x) has x intercepts then the solutions are real
Let us use remainder theorem and change of signs rule
f(0) = 1>0
f(-1) = -1+3+1=3
f(-2) = -32+6+1<0
This implies there is a real root between -1 and -2.
f(1) = -1
Since f(0) and f(1) have different signs, there exists a real root between 0 and 1.
f(2) = 32-6+1>0
Since f(1) and f(2) have different signs there exists a real root between 1 and 2.
Thus there are definitely three real solutions as
one between -1 and 0, one between 0 and 1, and third between 1 and 2.
Answer:
they both have right angles
Answer:
12
Step-by-step explanation: 12:3=4, 4 x 2= 8
Answer:
39
Work:
(x+5)/2=22
We will reverse this equation.
We will start by moving the 2 through inverse operations.
22x2=44
Now we have the equation
x+5=44
We will subtract 5
44-5=39
x=39
the unknown variable equals 39
Kali had 39 CDs on Monday