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Elodia [21]
3 years ago
7

Estimate the sum of $642.23 and $861.17 to the nearest hundred dollars

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0
Estimate the sum of $642.23 and $861.17 to the nearest hundred dollars
600 +900=1500
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Tara has 3/4 cup of ice cream. How many 1/5 -cup servings are in 3/4 cup of ice cream?​
saw5 [17]

Answer:

4/15

Step-by-step explanation:

because 1/5÷3/4=4/15

8 0
3 years ago
NetSell, a the TV remote control supplier for Lumyn Electronics, has a weekly production cost of q TV remote controls that is gi
natali 33 [55]

Answer:

a.  \frac{dC(q)}{dq} = 0.000012q^2 -0.06q + 100

b. \frac{dR(q)}{dq}=-0.01q+200

c.

U'(2000)=-0.000012(2000)^2+0.05(2000)+100 = 152

U'(7000)=-0.000012(7000)^2+0.05(7000)+100 = -138

 

Step-by-step explanation:

a) The marginal cost function is given by the derivative of the total cost function, in this way the marginal cost function for this company is:

\frac{dC(q)}{dq} = \frac{dC(q)}{dq} (0.000004q^ 3 - 0.03q ^ 2 + 100q + 75000) = 0.000012q^2 -0.06q + 100

b) The income function is given by the relation R (q) = P (q) q = -0.005q^2 + 200q.

The marginal revenue function for the company is given by the derivative of the revenue function, in this way the marginal revenue function is:

\frac{dR(q)}{dq}= -0.01q+200

 

(c) The profit function of the company is given by the relation U (q) = R (q) - C (q), and the marginal utility function is given by the derivative of the utility function, in this way , the marginal utility function is:

\dfrac{dU(q)}{dq}=R'(q) - C'(q) = -0.01q+200 - (0.000012q^2-0.06q+100) = -0.000012q^2+0.05q+100

When q = 2000, the marginal utility is:

U'(2000)=-0.000012(2000)^2+0.05(2000)+100 = 152

When q = 7000, the marginal utility is:

U'(7000)=-0.000012(7000)^2+0.05(7000)+100 = -138

6 0
3 years ago
Simplify the expression -1/2(-5/6 + 1/3)
alexira [117]

Answer: 1/4

Step-by-step explanation:

​​-

5 0
3 years ago
Simplify the expression
Molodets [167]

Answer:

8x^8/3 y^4 - The first option

Step-by-step explanation:

The first thing we need to do is the exponent outside the bracket and leave the 8 till last, because exponents always come before multiplying coefficients. When an term with an exponent is multiplied by another exponent outside a bracket, the exponents of both terms are multiplied by the exponent outside the bracket.

This means that the expression is now:

8(x^2*4/3 y^3*4/3)

First we can so the x term. The x term already has an exponent of 2, so the 2 is multiplied by the 4/3 exponent outside the bracket. 2*4/3 = 8/3, so the x term is now: x^8/3

The same happens to the y term: 3*4/3 simplifies to 4, so the y term is now y^4.

So now our expression is:

8(x^8/3 y^4)

Now the 8 outside the bracket simply multiplies on to the whole term so we finish with:

8x^8/3 y^4 - The first option.

Hope this helped!

7 0
3 years ago
What is the slope that goes through (6,-7),(-5,-2)
agasfer [191]
Slop=(y2-y1)/(x2-x1)
Slop=(-2-(-7))/(-5-6)
Slop=-5/11
7 0
3 years ago
Read 2 more answers
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