Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
Answer:
- |t -(-5)| = 1.5
- [-6.5, -3.5] = [minimum, maximum]
Step-by-step explanation:
The magnitude of the difference between the temperature (t) and -5 will be 1.5 at the limits:
|t -(-5)| = 1.5
This is equivalent to two equations:
In each case, the equation is solved by subtracting 5 from both sides:
- t = -6.5 . . . . minimum allowed temperature
- t = -3.5 . . . . maximum allowed temperature
Answer:
Option a) 50% of output expected to be less than or equal to the mean.
Step-by-step explanation:
We are given the following in the question:
The output of a process is stable and normally distributed.
Mean = 23.5
We have to find the percentage of output expected to be less than or equal to the mean.
Mean of a normal distribution.
- The mean of normal distribution divides the data into exactly two equal parts.
- 50% of data lies to the right of the mean.
- 50% of data lies to the right of the mean
Thus, by property of normal distribution 50% of output expected to be less than or equal to the mean.
Answer:
$89.1
Step-by-step explanation:
13.5 % of $660
= 13.5/ 100 × 660
= 0.135 × 660
= 89.1
hence, $ 89.1
Answer:
She gets a job as a lawyer after graduation.
Step-by-step explanation:
