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3 years ago

Which is a better buy 4 grapefruits for 80 cents or 12 grapefruits for $1.80?

Mathematics

1 answer:

PtichkaEL [24]3 years ago

8 0

12 grapefruit for 1.80. so if you multiply. 80 cents by 3=2.40 for 12 but 1.80 us cheaper

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(1)/(4)(x+y)-(3)/(6)y+(2)/(9)x-8x+4y

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3 years ago

12p < 96 A. p < 8 B. p < 108 C. p < 84 D. p > –8

inessss [21]

Solution:

Note that:

Given inequality: 12p < 96

Dividing both sides by 12:

12p < 96
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Correct option is A.

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3 years ago

Read 2 more answers

Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo

pav-90 [236]

Answer:

Probability distribution vector = $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$

Step-By-Step Explanation

If $P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)$ is the transition matrix for a Markov chain with two states.

$x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)$ be the initial state vector for the population.

$X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)$

$X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)$

In the long run, the probability distribution vector Xm approaches the probability distribution vector $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$ .

This is called the steady-state (or limiting,) distribution vector.

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3 years ago

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vladimir2022 [97]

Answer:

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Step-by-step explanation:

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Last summer he earned = 6.5 X 40 = 260

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Answer from Gauthmath

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shusha [124]

Answer:

Step-by-step explanation:

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