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arsen [322]
3 years ago
11

Which second degree polynomial function f(x) has a lead coefficient of 3 and roots 4 and 1?

Mathematics
2 answers:
Stella [2.4K]3 years ago
7 0

Answer:

f(x) = 3x² - 15x + 12

Step-by-step explanation:

Given f(x) has roots x = a and x = b, then

(x - a) and (x - b) are the factors

f(x) is then the product of the factors

f(x) = a(x - a)(x - b) ← where a is a multiplier

Given roots are x = 4 and x = 1, then

(x - 4) and (x - 1) are the factors

With a = 3, then

f(x) = 3(x - 4)(x - 1) ← expand factors using FOIL

     = 3(x² - 5x + 4) ← distribute

     = 3x² - 15x + 12

Sophie [7]3 years ago
5 0

Answer:

f(x) = 3x^2 - 15x + 12

Step-by-step explanation:

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The scale model of the car is 1:18 the length of the model is 9 1/2 inches how many feet long is the actual
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Answer:

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Step-by-step explanation:

1 inch of the model represents 18 inches of the real car. The car's dimensions are 18 times larger than the model's dimensions. Multiply the model dimension by 18 to find the corresponding real dimension.

9 1/2 * 18 = 9.5 * 18 = 171

The actual car is 171 inches long.

Now we need to convert 171 inches to ft.

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Since we want to eliminate inches and end up with feet, we divide both sides by 12 in.

(1 ft)/(12 in.) = 1

The conversion factor is (1 ft)/(12 in.) to go from inches to feet.

171 in. * (1 ft)/(12 in.) = 14.25 ft

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A) \frac{n^2}{2} + \frac{n}{2}

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Step-by-step explanation:

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