The cost per minute for a conference phone call originally 2.60 increased by 30% what is the new price?

2 answers:

6 0

c.) $3.38

Original price = $2.60
* It is the basis of increase thus, 100%
* The increase is 30%, thus, 100% + 30% = 130%

To get the new price, simply multiply the original price to 130%

$2.60 * 130% = $3.38

Another way of solving the problem is getting the equivalent of 30% and adding it to the original price.

$2.60 * 30% = $0.78
$2.60 + $0.78 = $3.38

Rom4ik [11]2 years ago

4 0

$2.60* (30/100)= $0.78

$2.60+ $0.78= $3.38

The correct answer is c. $3.38~

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Mr. Robredo is building a fence around a rectangular region with 36 feet of fencing. The area of the rectangular region is 65 sq

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P = 2(L + W)
P = 36
36 = 2(L + W)
36/2 = L + W
18 = L + W....L = 18 - W

A = L * W
A = 65
L = 18 - W

65 = W(18 - W)
65 = 18W - W^2
W^2 - 18W + 65 = 0
(W - 13)(W - 5) = 0

W - 13 = 0 .....L = 18 - 13
W = 13 L = 5

W - 5 = 0 L = 18 - 5
W = 5 L = 13

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3 years ago

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What is the probability that a point chosen at random in the given figure will be inside the larger square and outside the small

In-s [12.5K]

Answer:

P(inside larger square and outside smaller) = $\frac{51}{100}$

Step-by-step explanation:

Probability is the result of the division of the number of possible outcome by the number of an event.

In the question, for a point chosen, the point can be in the small square only or in the area or region between the small square and the big square as such,

Area of larger square = area of region between both squares + area of smaller square

Where the area of a square is S × S where S is the side of a square

Area of larger square = 10 × 10

= 100 cm square

Area of smaller square = 7 × 7

= 49 cm square

Area of the region between both squares

= 100 - 49

= 51 cm square

The probability that a dot selected is inside the larger square and outside the smaller is

P(inside larger square and outside smaller) = Area of region between both square/ Area of larger square

P(inside larger square and outside smaller) = $\frac{51}{100}$