The bowling ball will require more force to roll because it is more massive.
Acceleration x time = velocity
Since you're given acceleration and time, just plug the values into the equation.
3
x 1.1 s = ?
Solve that equation, and remember your velocity should be in m/s.
First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.
Therefore mass× gravitational pull×height will give us the work done
=3.2kg ×9.8N/kg×1.2m
=37.632J
then, the work done over the 25m distance if found by the following formula: work done=force×distance
=1.0N×25m
=25J
On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.
therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m
=m×g×h
=3.2kg×9.8N/kg×1.1m
=34.496J
To get the total we add the amount of work done in the various instances.
Answer:
a) p = m1 v1 + m2 v2
, b) dp / dt = m1 a1 + m2 a2
, c) It is equivalent to force
dp / dt = 0
Explanation:
In this problem we have two blocks and the system is formed by the two bodies.
Part A. Initially they ask us to find the moment of the whole system
p = m1 v1 + m2 v2
Part B.
Find the derivative
dp / dt = m1 dv1dt + m2 dv2 / dt
dp / dt = m1 a1 + m2 a2
Part C.
Let's analyze the dimensions
m a = [kg] [m / s2] = [N]
It is equivalent to force
Part d
Acceleration is due to a net force applied
Part e
The acceleration of block 1 is due to the force exerted by block 2 during the moment change
Part f
Force of block 1 on block 2
True f12 = m1a1 f21 = m2a2
Part g
By the law of action and reaction are equal magnitude F12 = f21
Part H
dp / dt = 0
Isolated system F12 = F21 and the masses are constant. The total moment is only redistributed
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