Answer:
K = 1.08 X 10¹²
Explanation:
The solved solution is in the attach document
NaBr (aq) + _H3PO4 (aq) → _Na3PO4(aq) + _HBr (aq)<br>
3,1,1,3<br>
1,2,3,1<br>
3,1,3,1<br>
1,1,3,3
BaLLatris [955]
Answer:
A 3,1,1,3
Explanation:
hope the picture help u to understand :)
Answer:
The empirical formula is C2H6O
Explanation:
Please see attachment for explanation on how to solve for the empirical formula.
Answer:

------->
+ 

Explanation:
In equation 1, equating the mass number (A) on both sides.
A = 235 + 1 = A + 94 + 3*1
236 = A + 94 + 3
A = 236 - 94 = 3
A = 139
Equate the atomic numbers on both sides
92 + 0 = Z + 36 + 3*0
92 = Z + 36
Z = 92 - 36
Z = 56
In reaction 2, equating the mass number on both sides
235 + 1 = A + 143 + 3 *1
236 = A + 143 + 3
236 = Z + 146
Z = 90
Equatoing the atomic number of both sides
92 + 0 = Z + 54 + 3*0
92 = Z + 54
Z = 92 - 54
Z = 38.
EN is the tendency of atom to attract the bonding pair of elecrons toward itself so as we move across period the size of atom remains same and nuclear charge increses so it can attract valance shell more tightly toward it and also the bonding pair which is formed and its vice versa in group