Answer:
1/10^2
Step-by-step explanation:
Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵ 
∴ 
≅ 736.2 to the nearest tenth foot
Answer:
true
Step-by-step explanation: bro please give the branleist please really need it
I got B but I'll show you how I got that answer.
Let's look at AB and BC. AB = 3 and BC = 4.
3/4 = 0.75
On the triangle, AB = 90. And BC = 10x - 20. We need to solve for x and prove that AB/BC = 0.75.
Let's start with Choice A.
10(11) - 20 = 90.
AB = 90
BC = 90.
90/90 = 1. It doesn't equal 0.75. Meaning this answer is wrong.
Now let's look at Choice B.
10(14) - 20 = 120.
AB = 90
BC = 120
90/120 = 0.75
So, 3:4 = 90:120 making Choice B the correct Answer. Let me know if this is correct
Answer: 2
(
x
+
4
)
Step-by-step explanation:
