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emmainna [20.7K]
2 years ago
5

Carol is ordering bricks for two large construction jobs at the same location. The first job needs 500 bricks every day for 9 da

ys and the second job needs 700 bricks every day for 9 days. What is the total number of bricks Carol needs for both jobs?​
Mathematics
1 answer:
sergey [27]2 years ago
4 0

Answer:

10,800

Step-by-step explanation:

500 X 9 = 4,500

700 X 9 = 6,300

4,500 + 6,300 = 10,800

The total number of bricks Carol needs for both jobs is 10,800.

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pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

104=1\times 2\times 2\times 2\times 13

88=1\times 2\times 2\times 2\times 11

Form above , we can say that common factors are :

HCF=2\times 2\times 2=8

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

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