Write the decimal number as a fraction
(over 1)
0.87 = 0.87 / 1
Multiplying by 1 to eliminate 2 decimal places
we multiply top and bottom by 2 10's
Numerator (N)
N = 0.87 × 10 × 10 = 87
Denominator (D)
D = 1 × 10 × 10 = 100
N / D = 87 / 100
Simplifying our fraction
= 87/100
<span>= 87/100</span>
2.85 = 2 17/20 - hope it helps!
Answer: x^3+30x+75
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15x
Step-by-step explanation:
5x/x^2+2x÷30x^2/x+2
1/15x^5+2x^3+5x^2
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x^3
x^3+30x+75
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15x
Answer:
8
Step-by-step explanation:
Answer: 8 batches
Step-by-step explanation:
To get the number of batches she made, we can just use proportion to solve it. But first, we need to convert 5 1/3 to improper fraction
5 1/3 = 16/3
Then we can now use the proportion to solve
2/3 cups = 1 batch
16/3 cups = x (note:5 1/3=16/3)
cross multiply
2/3 × x = 16 /3
2x/ 3 = 16/3
we need to make x the subject of the formula, to do that we will multiply each side of the equation by 3/2
2/3 × 3/2 x = 16/3 × 3/2
6x /6 = 48 / 6
x = 8
Therefore she made 8 batches of cookies.
Answer: " (3,1) is the point that is halfway between <em>A</em> and <em>B</em>. "
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Explanation:
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We know that there is a "straight line segment" along the y-axis between
"point A" and "point B" ; since, we are given that:
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1) Points A, B, C, and D form a rectangle; AND:
2) We are given the coordinates for each of the 4 (FOUR points); AND:
3) The coordinates of "Point A" (3,4) and "Point B" (3, -2) ; have the same "x-coordinate" value.
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We are asked to find the point that is "half-way" between A and B.
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We know that the x-coordinate of this "half-way" point is three.
We can look at the "y-coordinates" of BOTH "Point A" and "Point B".
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which are "4" and "-2", respectively.
Now, let us determine the MAGNITUDE of the number of points along the "y-axis" between "y = 4" and y = -2 .
The answer is: "6" ; since, from y = -2 to 0 , there are 2 points, or 2 "units" from y = -2 to y = 0 ; then, from y = 0 to y = 4, there are 4 points, or 4 "units".
Adding these together, 2 + 4 = 6 units.
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So, the "half-way" point would be 1/2 of 6 units, or 3 units.
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So, from y = -2 to y = 4 ; we could count 3 units between these points, along the "y-axis". Note, we could count "2" units from "y = -2" to "y = 0".
Then we could count one more unit, for a total of 3 units; from y = 0 to y = 1; and that would be the answer (y-coordinate of the point).
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Alternately, or to check this answer, we could determine the "halfway" point along the "y-axis" from "y = 4" to "y = -2" ; by counting 3 units along the "y-axis" ; starting starting with "y = 4" ; note: 4 - 3 = 1 ; which is the "y-coordinate" of our answer; that is: "y = 1" ; and the same y-coordinate we have from the previous (aforementioned) method above.
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We know the "x-coordinate" is "3" ; so the answer:
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" (3,1) is the point that is halfway between <em>A</em> and<em> B </em>."
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