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garik1379 [7]
3 years ago
7

Anyone want to ta lk plz dont report or delete

Mathematics
2 answers:
maks197457 [2]3 years ago
6 0

i dont know thanks for the points tho

givi [52]3 years ago
4 0

Answer:

hey hru

Step-by-step explanation:

and id.k the answer to the second question

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What is mKNL?<br> Enter your answer in the box.
sergejj [24]

Answer:

102°

Step-by-step explanation:

As the vertically opposite angles are equal,

5x+2={3(x+14)

Now let's solve for x now

5x+2=3(x+14)\\

5x+2=3x+42

5x-3x=42-2

2x=40

\frac{2x}{2} =\frac{40}{2}

x=20 \\

Now let's find the value of KNL

3(x+14)\\3(20+14)\\3*34\\102

Hope this helps you.

Let me know if you have any other questions ;-)

5 0
2 years ago
Simplify 3x+6=18, please
Fiesta28 [93]

Answer:

x = 4

Step-by-step explanation:

Step 1: Write out equation

3x + 6 = 18

Step 2: Subtract 6 on both sides

3x = 12

Step 3: Divide both sides by 3

x = 4

7 0
3 years ago
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PLEASE HELP I WILL GIVE BRAINLEIST
lina2011 [118]

Answer:

They help you see progressions but sometimes graphs can be manipulated to convey specific data and hide others like using methods called cherry picking, changing x and y axis and etc.

7 0
3 years ago
Find the sum of 2y²+3yz-y²-yz-z²+6zy-3y² please help STEP explanation ​
larisa86 [58]

Answer:

See picture attached

Step-by-step explanation:

I hope this helps you.

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7 0
3 years ago
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I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0
3 years ago
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