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Citrus2011 [14]

3 years ago

14

Ana, Bill, and Charles are getting ready to pose for a photograph. How many different ways could they line up for the picture so

that Ana and Bill are standing next to each other?

2 answers:

Alik [6]3 years ago

8 0

The answer is 6 based on probability but answer is 4 on apex hope this helps

umka21 [38]3 years ago

6 0

There are two ways of Anna-Bill standing next to each other when Anna is on the left side of Bill. See below.
$\boxed{AB}C$
$C\boxed{AB}$

There are two ways of Bill-Anna standing next to each other when Bill is on the left side of Anna. See below.
$\boxed{BA}C$
$C\boxed{BA}$

There are 4 different ways

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Can someone please help. Please show work

FinnZ [79.3K]

Answer:

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5 0

3 years ago

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Determine the sum of the first twenty five terms of the sequence whose first five terms are 5,14,23,32 and 41

Alika [10]

Answer:

Step-by-step explanation:

This is an arithmetic sequence. Each term is 9 more than the preceding term.

The 25th term is 5+24*9 = 1085.

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2 years ago

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marta [7]

So what u need to do is

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3 years ago

100 PTS!! PLEASE HELP! OVER DUE

Reika [66]

Answer:

$-\frac{1}{2} \vec {c}$

Step-by-step explanation:

Look at the component form of each vector.

Note that vector c is <4,4> and vector d is <-2,-2>

If one imagined the line that contained each vector, the line for both would have a slope of 1, because $\frac{4}{4}=1=\frac{-2}{-2}$

Since they have the same slope they are parallel, but since they are in opposite directions, we often call them "anti-parallel" (simply meaning parallel, but in opposite directions).

If two vectors are parallel, one vector can be multiplied by a scalar to result in the other vector. This means that there is some number "k", such that $k \vec{c} = \vec {d}$ , or equivalently, $kc_x=d_x$ and $kc_y=d_y$ .

If $kc_x=d_x$ and $kc_y=d_y$ , we just need to substitute known values and solve for k:

$kc_x=d_x\\k(4)=(-2)\\k=\dfrac{-2}{4}\\k=-\frac{1}{2}$

Double checking that k works for the y-coordinates as well:

$kc_y=d_y$

$(-\frac{1}{2}) (4)$ ? $(-2)$

$-2=-2 \text{ } \checkmark$

So, $-\frac{1}{2} \vec {c} = \vec {d}$

6 0

2 years ago

From first principles, find the indicated derivatives

LenaWriter [7]

By definition of the derivative,

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)$

$\displaystyle\frac{dr}{ds} = \frac{3s^2}2$

6 0

2 years ago