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Roman55 [17]
3 years ago
5

In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m a

way from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light?
Physics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

214.3 x 10⁻⁹ m or 214.3 nm

Explanation:

d = slit separation in the experiment = 3.00 x 10⁻⁵ m

D = screen distance from the slits = 2.00 m

n = Order of the bright fringe = 7

λ = Wavelength of the light

y = distance of the bright fringe from the central bright fringe = 10 cm = 0.10 m

Position of the bright fringe is given as

y = \frac{nD\lambda }{d}

0.10 = \frac{(7)(2)\lambda }{3.00\times 10^{-5}}

λ = 214.3 x 10⁻⁹ m

λ = 214.3 nm

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weqwewe [10]

0.39 cm is the compression in the spring by atmospheric pressure. Work done by the atmospheric pressure is 0.031J in compressing the spring.

a) When the air beneath the piston is completely pumped out, then formula for the atmospheric pressure causing the spring to compress will be: p°A = kx

where, x= compression, A= area, p°= atmospheric pressure and k= spring constant

Now, p°A = kx

x = p°A/x

x = p° (πr²)/k

Putting the values: x= {(1.0 × 10⁵) × π × (0.023)²}/4200

x= 0.0039 meter

Thus, x= 0.39 cm is the compression in the spring.

b) work done by the atmospheric pressure to compress the spring will be: W=(1/2)kx²

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Now, W=(1/2)kx²

W= (1/2) × 4200 × (0.0039)²

W= 0.031 Joule

Thus, work done by the atmospheric pressure is 0.031J.

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5 0
1 year ago
Which physical phenomenon causes the spherical shapes of raindrops
jeyben [28]

Answer:

Raindrops start to form in a roughly spherical structure due to the surface tension of water. This surface tension is the "skin" of a body of water that makes the molecules stick together. The cause is the weak hydrogen bonds that occur between water molecules.

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What does "the matter that you start with in a chemical reaction"
myrzilka [38]
The product is the what you start with in a chemical reaction
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4 years ago
A certain planet has a radius of 4990 km. If, on the surface of that planet, a 95.0 kg object has a weight of 591 N, then what i
aniked [119]

Answer:

3743.489 kg

Explanation:

F_g = 591 N

G = 6.674x10^-11 constant of gravity

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591 N = 6.674x10^-11[(95*m_2)/4990^2]

8.855 = [(95*m_2)/4990^2]

355631.472 = 95*m_2

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4 years ago
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If the mass is doubled the frequency will be multiplied by 4

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