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Roman55 [17]
3 years ago
5

In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m a

way from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light?
Physics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

214.3 x 10⁻⁹ m or 214.3 nm

Explanation:

d = slit separation in the experiment = 3.00 x 10⁻⁵ m

D = screen distance from the slits = 2.00 m

n = Order of the bright fringe = 7

λ = Wavelength of the light

y = distance of the bright fringe from the central bright fringe = 10 cm = 0.10 m

Position of the bright fringe is given as

y = \frac{nD\lambda }{d}

0.10 = \frac{(7)(2)\lambda }{3.00\times 10^{-5}}

λ = 214.3 x 10⁻⁹ m

λ = 214.3 nm

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Answer:

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Explanation:

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Which in our case will be:

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A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 22 ft/s2. What is the dist
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The correct solution is "122.2211".

Explanation:

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Initial velocity,

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Specific Heat= 0.39<span>

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