Question

In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light?

Answer 1

Answer:

214.3 x 10⁻⁹ m or 214.3 nm

Explanation:

$d$ = slit separation in the experiment = 3.00 x 10⁻⁵ m

$D$ = screen distance from the slits = 2.00 m

$n$ = Order of the bright fringe = 7

λ = Wavelength of the light

$y$ = distance of the bright fringe from the central bright fringe = 10 cm = 0.10 m

Position of the bright fringe is given as

$y = \frac{nD\lambda }{d}$

$0.10 = \frac{(7)(2)\lambda }{3.00\times 10^{-5}}$

λ = 214.3 x 10⁻⁹ m

λ = 214.3 nm