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myrzilka [38]
3 years ago
6

Calculate the gravitational potential energy relative to the ground when an 82 kg person climbs to the top of a 2.0 m stepladder

.
Physics
1 answer:
bezimeni [28]3 years ago
6 0
Maybe 164.... not to sure though, sorry


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spin [16.1K]

I need you to make me an invented poem written please not in image

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2 years ago
In Hooke's law, Fspring=kΔx , what does the Fspring stand for?
Mrrafil [7]

Answer:

The amount of force acting on the spring.

Explanation:

Here, Fspring= kΔx  is a equation denoting the amount of force acting on the spring.

where, k = spring constant.

           Δx= change in the length of the spring.

so, for every Δx change in spring length, kΔx force acts on the spring.

6 0
3 years ago
Read 2 more answers
What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?Use 1.67×
vazorg [7]

The electric force on the proton is:

F = Eq

F = electric force, E = electric field strength, q = proton charge

The gravitational force on the proton is:

F = mg

F = gravitational force, m = proton mass, g = gravitational acceleration

Since the electric force and gravitational force balance each other out, set their magnitudes equal to each other:

Eq = mg

Given values:

q = 1.60×10⁻¹⁹C, m = 1.67×10⁻²⁷kg, g = 9.81m/s²

Plug in and solve for E:

E(1.60×10⁻¹⁹) = 1.67×10⁻²⁷(9.81)

E = 1.02×10⁻⁷N/C

5 0
3 years ago
A star produces energy by? ( a p e x )
katen-ka-za [31]

Answer and Explanation:

Stars create energy primarily through the fusion of hydrogen into helium through nuclear reactions.

3 0
3 years ago
An automobile has a mass of 1200 kg. what is its kinetic energy, in kj, relative to the road when traveling at a velocity of 50
snow_lady [41]
One thing you should notice. It is kind of weird. Ke has no direction so that fact that it has velocities associated with it does not matter. It becomes a scaler (something measured by amount alone).

General Formula
Ke = 1/2 m v^2
Formula for this problem
Ke = 1/2 m (v2)^2 - 1/2 m (v1)^2

Givens
m = 1200 kg
v2 = 100 km/hr = 100 km/h * [1 hour / 3600 sec] * [1000 m/ 1km] = 27.8 m/s
v1 = 50 km / hr = 13.9 m/s

Substitution and work.
================
delta Ke = 1/2 1200 (27.8)^2 - 1/2 1200 (13.9)^2
delta Ke = 463704 - 115926
delta Ke = 34778 Joules
delta Ke = 34.8 kJ

The change is 34.8 kJ which means that the vehicle gains 34.8 kJ

5 0
3 years ago
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