<span>Find force,
9.8 m/s2 x 5.24 kg = </span><span>51.352 N </span>
Find work,
<span><span>51.352 N x 1.63 m= </span><span>83.70 N*m
</span>Example:
To solve this given word problem we can first identify the given and the apt formula to use in this phenomenon: Given: Force = 4, 500 N = 4, 500 kg-m/s^2 Acceleration = 5 m/s^2 </span>
<span>Formula: f=ma </span>
<span>Derivation: m = f/a </span>
<span>Solution: </span><span><span>
1. </span>M = f/a</span> <span><span>
2. </span>M = 4,500 kg-m/s^2 / 5 m/s^2</span> <span><span>
3. </span>M = 900 kg </span>
<span>Hence, the object’s mass is </span>900 kg.<span>
</span>
15,409/1 or 61636/4 both fractions I can try a expression which is 5(3000+81.8)
Answer:
29
Step-by-step explanation:
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
Answer:
The answer is 52
Step-by-step explanation:
This problem is perimeter so you add 11 plus 11 plus 15 plus 15 to get 52.
