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ANEK [815]
3 years ago
12

two times a number plus one is greater than five and less than seven. (write an inequality) and solve

Mathematics
1 answer:
Sloan [31]3 years ago
5 0
5 ≤ 2x+1 ≤ 7
Do not write the line underneath the greater than sign, it was the only sign available
x = 2.5
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Given collinear points E, F and G such that point F is the midpoint of segment EG. Find the new length of EG given that EF =5x+9
Veseljchak [2.6K]

Answer:

The length of EG is 58 units

Step-by-step explanation:

The midpoint of a segment divides it into two equal part

Let us use this rule to solve our question

∵ E, F, and G are collinear points

∵ Point F is the midpoint of segment EG

→ That means F divides EG into 2 equal segments EF and FG

∴ EF = FG

∵ EF = 5x + 9

∵ FG = 3x + 17

→ Equate them

∴ 5x + 9 = 3x + 17

→ Subtract 3x from both sides

∵ 5x - 3x + 9 = 3x - 3x + 17

∴ 2x + 9 = 17

→ Subtract 9 from both sides

∴ 2x + 9 - 9 = 17 - 9

∴ 2x = 8

→ Divide both sides by 2 to find x

∵ \frac{2x}{2}=\frac{8}{2}

∴ x = 4

→ Substitute x by 4 in EF and FG to find their lengths

∵ EF = 5(4) + 9 = 20 + 9 = 29

∵ FG = 3(4) + 17 = 12 = 17 = 29

∵ EG = EF + FG

∴ EG = 29 + 29 = 58

∴ The length of EG is 58 units

6 0
3 years ago
A lawn mower is pushed a distance of 100 ft. Along a horizontal path by a constant force of 60 lbs. Yhe handle of the lawn mower
olga2289 [7]
For this case we have the following equation:
 w = || F || • || PQ || costheta
 Where,
 || F ||: force vector module
 || PQ ||: distance module
 costheta: cosine of the angle between the force vector and the distance vector.
 Substituting values:
 w = (60) * (100) * (cos (45))
 w = 4242.640687 lb.ft
 Answer:
 
The work done pushing the lawn mower is: 
 w = 4242.640687 lb.ft
6 0
3 years ago
Dose the perimeter of a square vary directly with the side length?
tankabanditka [31]

Yes, it does.

it is because, Perimeter of square = 4 L


5 0
3 years ago
Read 2 more answers
On Saturday, 90 people visited a museum, Tickets to the museum cost
AveGali [126]

Answer:

64 adult tickets were sold

Step-by-step explanation:

Let a = adult tickets sold

c = child tickets sold

a+c = 90  since there were 90 tickets sold

12a+7c = 950  since the amount of money collect is 950

c = 90-a

Substitute this into the second equation

12a +7( 90-a) = 950

Distribute

12a + 630-7a = 950

Combine like terms

5a +630 = 950

Subtract 630 from each side

5a = 950-630

5a = 320

Divide by 5

5a/5 = 320/5

a =64

64 adult tickets were sold

3 0
3 years ago
This question is from the similarity chapter. It would be really kind of you if you would answer this question.
katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

<u>2) Prove similarity</u>

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

  1. Angles AYX and ACB are corresponding and they both measure 90 degrees
  2. Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

<u>3) Solve for part A</u>

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

\frac{XY}{BC}=\frac{AY}{AC}

Plug in known values

\frac{2}{300}=\frac{11}{AC}

Cross-multiply

2AC=11*300\\2AC=3300\\AC=1650

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

<u>4) Solve for part B</u>

To find the length of AB, we can use the Pythagorean theorem:

a^2+b^2=c^2 where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0
3 years ago
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