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8090 [49]
3 years ago
15

Value of cos^2 (48) - sin^2 (12)?

Mathematics
1 answer:
Andrew [12]3 years ago
5 0
The value of that <span>(√5 + 1)/8 and We can prove it like this:
</span>cos 2A= 2cos^2 A-1=1-2sin^2 A 
<span>so cos^2 48 – sin^2 12 </span>
<span>=(1/2)(1+cos 96) - (1/2)(1-cos24) </span>
<span>=(1/2)(cos 96 +cos 24) and using cos(A)+cosB)=2cos((A+B)/2)cos((A-B)/2) </span>
<span>=cos60cos36 </span>
<span>=(1/2)cos36 </span>
<span>and you have to find cos36. </span>
<span>Suppose 5x=180, then </span>
<span>cos(5x)=cos(180) then x=-180,-108, -36, 36, 108 </span>
<span>Also 3x=180-2x </span>
<span>so cos(3x)=cos(180-2x)=-cos2x </span>
<span>so 4cos^3(x) -3cos(x)=1 - 2cos^2(x) </span>
<span>giving 4c^3+2c^2 - 3c-1=0 where c=cosx </span>
<span>c=-1 is a root and factorizing gives </span>
<span>(c+1)(4c^2-2c-1)=0 </span>
<span>so 4c^-2c-1=0 giving </span>
<span>c=(2±√20)/8=(1±√5)/4 and these have values cos(36) and cos(108) </span>
<span>the positive root is therefore cos(36)=(1+√5)/4 </span>
<span>and the required value (1/2)cos(36)=(1+√5)/8
</span>I think this can be very useful
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