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2 years ago

There are 48 players and 6 coaches on Brian's football team. What is the ratio of players to coaches?

Mathematics

2 answers:

Rainbow [258]2 years ago

8 0

Answer:

players to coach ratio.

What is a ratio, a ratio is diplayed like this 2:3

If you were to put the ration of -> players:coach

The ratio would be 48:6

yes, you can simplify a ration,

48/6 = 8

6/6 = 1

ration is 8:1

stiv31 [10]2 years ago

8 0

Answer:

8:1

Step-by-step explanation:

48:6 = 8:1

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If y is directly proportional to x square and y equal 1/8 when x = 1/2 what is the positive value of x when y it was 9/2?

mojhsa [17]

Answer:

Step-by-step explanation:

Given y is directly proportional to x² then the equation relating them is

y = kx² ← k is the constant of proportion

To find k use the condition y = $\frac{1}{8}$ when x = $\frac{1}{2}$ , then

$\frac{1}{8}$ = k( $\frac{1}{2}$ )² = $\frac{1}{4}$ k ( multiply both sides by 8 )

1 = 2k ( divide both sides by 2 )

k = $\frac{1}{2}$

y = $\frac{1}{2}$ x² ← equation of proportion

When y = $\frac{9}{2}$ , then

$\frac{9}{2}$ = $\frac{1}{2}$ x² ( multiply both sides by 2 )

9 = x² ( take the square root of both sides )

x = ± $\sqrt{9}$ = ± 3

with positive value x = 3 → d

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3 years ago

Find the surface area of a cylinder

IceJOKER [234]

A = 2•3.14•3•8 + 2•3.14•3^2 = 207.34512

6 0

2 years ago

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Wewaii [24]

Answer:

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Step-by-step explanation:

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3 years ago

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Please help. 2/3 (x - 6) = 6

vagabundo [1.1K]

Answer:

6=6

Step-by-step explanation

if 2/3x=10

therefore

x=3/2x10

x=15

substitute x with 15

2/3 (15 - 6)=6

2/3(9)=6

6=6

6 0

2 years ago

In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a

nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

$\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ}$ ;

$\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ}$ ;

$\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q$ .

Also,

$\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P$ in right triangle PBM.

Thus $\rm \angle{P\hat{B}M} = \angle C\hat{M}Q$ .

Additionally $\rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}$ .

Therefore $\rm \triangle PBM \sim \triangle MCQ$ .

$\rm \displaystyle BC = 2\;MC$ for M is the midpoint of segment BC.

$\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC$ .

$\rm \triangle PBM \sim \triangle MCQ$ implies that

$\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3$ .

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2 years ago