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Anni [7]
2 years ago
5

Angie babysits to earn extra spending money. She recorded how much money she earned

Mathematics
1 answer:
il63 [147K]2 years ago
7 0

Answer: $50

Step-by-step explanation:

Given

Money earned each time is given as

10, 20, 30, 40, 50, 60

The range is given by the difference of the highest and lowest value of the given data

Highest value=60

lowest value=10

\Rightarrow \text{Range=60-10}\\\Rightarrow \text{Range=}\$50

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The measurement is 51
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3 years ago
Is -3y = 5x + 4 perpendicular
aivan3 [116]

Answer:

no it is not perpedicular

Step-by-step explanation:

I plugged the equation into a graphing calculator and the line does not appear to be perpendicular

5 0
3 years ago
Read 2 more answers
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
5. The length of a rectangular swimming pool is 50 yards, and the width of the pool is 16
d1i1m1o1n [39]
The answer is C. I got this by doing a^2 + b^2= c^2. 50^2 + 16^2=c^2, 2500 + 256 = c^2, 2756 = c^2, then you take the square root of 2756 and that gives you your answer 52.50 yards. Hope this helps :D
7 0
2 years ago
(5, 3) and (6, r) m = -1
Rzqust [24]

Answer:

r = 2

Step-by-step explanation:

(2-3)/(6-5)

= -1/1

= -1

6 0
3 years ago
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