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Nastasia [14]
3 years ago
15

2) Eighty students were surveyed as they left the cafeteria after lunch. The following were

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

I believe that 11 students ate only the cookie.

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A caterer charges $120 to cater a party for 15 people and $200 for 25 people. Assume that the cost, y, is a linear function of t
DIA [1.3K]

Answer:

The equation in slope-intercept form is y = 8x

The slope represents the unit cost

A party for 40 people would cost $320

Step-by-step explanation:

8 0
3 years ago
Suppose that a linear model is appropriate when comparing the height of children to age. The heights of 30 children, aged 5 to 9
Elanso [62]

Answer:

The linear model will give a good approximation if the new value is within or close to the values we used to construct the linear model.

Step-by-step explanation:

A linear model gives reasonable approximations under these two conditions:

  1. If the value for which we need to use the approximation is within the range of values we used to construct the linear model
  2. If the value for which we need to use the approximation is close to the values which we used to construct the linear model.

For the given model, heights of children aged 5 to 9 were recorded. Here, age is the independent variable and height will be the independent variable. Heights of 30 children from age 5 to 9 were recorded and a linear model was constructed. Now, we need to tell which value of age can be made an input of this function to find the approximate height.

Using the above two principles, the linear model will give a good approximate if:

  1. The age of the child is between 5 and 9 years. In this situation, the value approximated by the model will be closer to the actual height in majority of the cases. For example, the model will give good approximations for children of ages 6, 6.5, 7, 7.75 etc
  2. The age of child is close to 5 and 9 years old but outside the range. In this case, the model will also give good approximations. For example. for a child of age 4.5 years or 10 years, the model will still give a good and reasonable approximations.
6 0
3 years ago
Interpret the 95% confidence interval for average BMI. What do the lower and upper bounds of the confidence interval tell us?
GaryK [48]

Answer:

(26.2252 ; 27.3748)

Step-by-step explanation:

The confidence interval is given by :

x ± Margin of error

The margin of error = Zcritical * (σ/√(n))

σ = 7.5 ; n = 654

Zcritical = Zα/2 = 1.96

The margin of error = 1.96 * (7.5/√654) = 0.5748

The confidence interval :

Upper boundary = 26.8 + 0.5748 = 27.3748

Lower boundary = 26.8 - 0.5748 = 26.2252

(26.2252 ; 27.3748)

We are 95% confident that the mean BMI of the entire population will fall in between (26.2252 ; 27.3748)

6 0
3 years ago
PLEASE ANSWER + BRAINLIEST!!!
Blizzard [7]
Ts option A

cos C = (b - x) / a
a cos C = b - x

x = b - a cosC
3 0
3 years ago
number 3 says,"If u and v are the measures of complementary angles such that sin u =2/5 and tan v =(square root of 21) 21/2, lab
vodomira [7]

Answer and Explanation:

Using trig ratios, we can express the given values of sin u and tan v as shown below

\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}

So we can go ahead and label the sides of the triangle as shown below;

We can find the value of u as shown below;

\begin{gathered} \sin u=\frac{2}{5} \\ u=\sin ^{-1}(\frac{2}{5}) \\ u=23.6^{\circ} \end{gathered}

We can find v as shown below;

\begin{gathered} u+v+90=180\text{   (sum of angles in a triangle)} \\ v+23.6+90=180 \\ v=180-113.6 \\ v=66.4^{\circ} \end{gathered}

5 0
1 year ago
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