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noname [10]
3 years ago
12

2. A submarine is able to raise and lower itself

Chemistry
1 answer:
Ronch [10]3 years ago
4 0

Answer:

I think it's the state of the surrounding water because if the water holds impurities it will float and if it doesn't have impurities it will sink

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identify the part of the slow carbon cycle in whitch the total amount of carbon is most likely decreasing and explain why this d
Westkost [7]

Answer:

i just had gthe sme question looked it up and got it WRONG

Explanation:

sorry i ont have a clue

3 0
3 years ago
Las Vegas Raiders' running back Josh Jacobs is 72 inches tall and has mass of 100 kg. Los
gladu [14]

Answer:

Josh is running at a speed of 9.09 yards per second.

Josh's velocity is 9.09 East.

Josh's force is 900 N.

Aaron Donald's force is 845 N.

Yes Josh scores the touchdown because he is faster and has more mass than Donald.

Explanation:

Josh scores the touchdown as he is heavier and faster than Donald.

Formulas are:

Force= mass x acceleration

Speed= distance divided by time.

Velocity= distance divided by time.

4 0
3 years ago
How much of a 10 M solution is needed to make 1 liter of all solution?
SashulF [63]

Answer:

b is the answer 1000ml

please mark me brainlist

4 0
3 years ago
What volume will be occupied by 33.0 grams of CO2 at 500 torr and 27 °C?
wlad13 [49]

Answer:

V = 27.98 L

Explanation:

Given data:

Mass of CO₂ = 33.0 g

Pressure = 500 torr

Temperature = 27°C

Volume occupied = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 33.0 g/ 44 g/mol

Number of moles = 0.75 mol

Volume of CO₂:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K  

Now we will convert the temperature.

27+273 = 300 K

Pressure = 500 /760 = 0.66 atm

By putting values,

0.66 atm×V = 0.75 mol × 0.0821 atm.L/ mol.K  × 300 K

V = 18.47 atm.L/0.66 atm

V = 27.98 L

4 0
2 years ago
A sample of an ionic compound NaA, where A- is the anion of a
vitfil [10]

Answer:

a) Kb = 10^-9

b) pH = 3.02

Explanation:

a) pH 5.0 titration with a 100 mL sample containing 500 mL of 0.10 M HCl, or 0.05 moles of HCl. Therefore we have the following:

[NaA] and [A-] = 0.05/0.6 = 0.083 M

Kb = Kw/Ka = 10^-14/[H+] = 10^-14/10^-5 = 10^-9

b) For the stoichiometric point in the titration, 0.100 moles of NaA have to be found in a 1.1L solution, and this is equal to:

[A-] = [H+] = (0.1 L)*(1 M)/1.1 L = 0.091 M

pKb = 10^-9

Ka = 10^-5

HA = H+ + A-

Ka = 10^-5 = ([H+]*[A-])/[HA] = [H+]^2/(0.091 - [H+])

[H+]^2 + 10^5 * [H+] - 10^-5 * 0.091 = 0

Clearing [H+]:

[H+] = 0.00095 M

pH = -log([H+]) = -log(0.00095) = 3.02

6 0
3 years ago
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