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RoseWind [281]
3 years ago
10

¿Cuál es la diferencia entre los compuestos alifáticos y ciclicos?

Chemistry
2 answers:
yan [13]3 years ago
7 0

Answer:

huh

Explanation:

lana [24]3 years ago
6 0

Answer:

I don't really understand

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Calculate the equilibrium constant for each of the reactions at 25 ∘C. 2Fe3+(aq)+3Sn(s)→2Fe(s)+3Sn2+(aq)
iragen [17]
We take activities of Solids and liquids equal 1. The reason is there concentrations not at all change amount of reactant at equilibrium in the reaction. Hence we don't consider concentrations of pure solids and liquids while writing equilibrium constant. So for above reaction, equilibrium constant (K) = [Sn^2 +] ^3 x 1 / [Fe^3+]^2 x 1. Ping me if you have any doubts.
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What did Rutherford observe that surprised him?
Valentin [98]

Answer:

Some of the Alpha particles shot at the gold foil bounced back.

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3 years ago
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How are the reactants represented in the chemical equation for photosynthesis? 6co2 o2 6co2 6h2o c6h12o6 6o2 c6h12o6 6h2o
Vika [28.1K]

The reactants of photosynthesis are represented by 6CO_2 and 6H_2O.

<h3>Photosynthesis</h3>

It is a reaction through which green plants make use of inorganic products such as water and carbon dioxide in the presence of solar radiation to make sugar. Oxygen is liberated as a by-product.

The equation of the reaction is represented by:

6CO_2 + 6H_2O --- > C_6H_{12}O_6 + 6O_2

Thus, the reactants are represented by  6CO_2 and 6H_2O respectively.

More on photosynthesis can be found here: brainly.com/question/1388366

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4 0
2 years ago
What volume of a 0.3300-m solution of sodium hydroxide would be required to titrate 15.00 ml of 0.1500 m oxalic acid? c2 o4 h2(a
shtirl [24]

Answer : 13.64 mL


Explanation : The reaction requires 13.64 mL of NaOH 

From the reaction we know that oxalic acid requires two moles of NaOH so we have to calculate the number of moles of both.

0.150 L X 0.1500 moles/L = 2.25 X 10^{-3}

So the moles of NaOH will be 2 X (2.25 X 10^{-3}) =  4.5 X 10^{-3}

Now, we know the concentration of NaOH as 0.330 M

4.5 X 10^{-3} moles / 0.330 moles/L = 0.01364 L or 13.64 mL

So, the volume of NaOH needed to neutralize oxalic acid will be 13.64 mL

8 0
3 years ago
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