Answer:
Amount of heat released when 25.0 g of (rubbing alcohol) is combusted equal to 98.7 kJ
Explanation:
According to balanced equation (as given in problem), combustion of 2 moles of rubbing alcohol release 474.28 kJ of heat.
Molar mass of (rubbing alcohol) = 60.095 g/mol
We know, number of moles of a compound is the ratio of mass to molar mass of that compound.
So, 2 moles of (rubbing alcohol) = (rubbing alcohol) = 120.19 g of (rubbing alcohol)
So, combustion of 120.19 g of rubbing alcohol release 474.28 kJ of heat.
Hence amount of heat released when 25.0 g of (rubbing alcohol) is combusted =
To solve the problem, use the equation
M1(V1) = M2(V2)
Where M1, M2 are the concentrations
V1, V2 are the volumes
Given V1 = 30.0 mL, M1 = 12.0 M
M2 = 0.16 M
Substituting to the equation,
(30)(12) = (V2)(0.16)
V2 = 2250 mL
There are 0.000882 gram in 882 ug