Answer:
MgCl₂(aq) + Al₂(CO₃)₂(aq) --> MgCO₃(s) + AlCl₃(aq)
Explanation:
Magnesium Chloride - MgCl₂
Aluminium Carbonate - Al₂(CO₃)₃
Magnesium carbonate - MgCO₃
Aluminium Chloride - AlCl₃
The equation of this reaction is given as;
MgCl₂(aq) + Al₂(CO₃)₃(aq) --> MgCO₃(s) + AlCl₃(aq)
Answer:
Any binary molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Explanation:
Going down in a group increases the atomic radius and a greater atomic radius implyes greater ionic radius.
When ionization takes place in these compounds they yelds protons (hidrogen ion) and an lewis base (anion). The greater the ionic radius the greater its stability, thus the periodic tendency is increaing the acidity of binary hidrogen compounds when going down a group. On the other hand going up a group decreases acidity, so any molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Below are I think the data for this problem:
Given the following data:
<span>Ca (s) + 2 C (graphite) → CaC2 (s) ∆H = -62.8 kJ </span>
<span>Ca (s) + ½ O¬2 (g) → CaO (s) ∆H = -635.5 kJ </span>
<span>CaO (s) + H2O (l) → Ca(OH)2 (aq) ∆H = -653.1 kJ </span>
<span>C2H2 (g) + 5/2 O¬2 (g) → 2 CO2 (g) + H2O (l) ∆H = -1300 kJ </span>
<span>C (graphite) + O¬2 (g) → CO2 (g) ∆H = -393.51 kJ
</span>
Below is the answer:
CaC2 (s) + 2 H2O (l) → Ca(OH)2 (aq) + C2H2 (g)
<span>So what you do is: </span>
<span>Times the first equation by -1 Second by 1 Third By 1 Fourth by -1 and Fifth by 2 </span>
<span>So This gives us: </span>
<span>1.CaC2--> Ca+2C </span>
<span>2.Ca+1/2O2-->CaO </span>
<span>3.CaO+H2O-->Ca(OH)2 </span>
<span>4.2CO2+H2O-->C2H2+5/2O2 </span>
<span>5.2C+202-->2CO2 </span>
<span>Now you cancel out like terms on either sides of the equation and you end up with </span>
<span>CaC2 (s) + 2 H2O (l) → Ca(OH)2 (aq) + C2H2 (g) Just what you wanted </span>
<span>So to calculate ∆H: </span>
<span>62.8-635.5-653.1+1300-787.02= -712.82</span>
In 1869, Mendeleev came up with the a law that describe the pattern of elements:“when the elements are arranged in order of increasing atomic mass, certain sets of properties recur periodically."
Mendeleev’s law describes the pattern of element in Mendeleev’s table.
The S and P blocks are known as orbitals