<span>The formula for iron bromide is FeBr^2 (one iron and 2 bromines)</span>
<u>Answer:</u> The temperature of the ideal gas is 
<u>Explanation:</u>
To calculate the temperature, we use the equation given by ideal gas equation:

where,
P = Pressure of the gas = 142,868 Pa = 142.868 kPa (Conversion factor: 1 kPa = 1000 Pa)
V = Volume of gas = 1.0000 L
n = number of moles of ideal gas = 0.0625 moles
R = Gas constant = 
T = temperature of the gas = ?
Putting values in above equation, we get:

Hence, the temperature of the ideal gas is 
The numerical value of Kc is 1.129 x10^4
<u><em> Explanation</em></u>
C3H6O +4O2→ 3 CO2 + 3H2O
KC is the ratio of concentration of the product over the reactant.
Each concentration of product and reactant are raised to the power of its coefficient.
Therefore the KC expression of equation above is
Kc=[ (Co2)^3 (H2O)^3] / [(C3H6O) (O2)^4)]
Kc =[(1.8^3) x (2.0^3)] / [(0.51) x (0.30^4)] =1.129 x10^4
Answer:
Density = 7.87 grams per mL
Explanation:
Density is given by the formula:

where
Z = effective number of atoms in one unit cell.
M = Molecular mass of the substance
a = edge length of unit cell
Na = Avogadro number = 6.022×10²³
In this case:
Z=2 as it is body-centered type unit cell
M = 56 g per mole for iron
a = 287 pm = 
Substituting the above values in the density formula we get:

Density of iron is 7.87 grams per mL.
Explanation:
The given data is as follows.
Energy needed for 1 mole = 279.7 kJ = 
= 279700 J
Therefore, energy required for 1 atom will be calculated as follows.

= 
As relation between energy and wavelength is as follows.
E = 
where, h = planck constant = 
c = speed of light = 
= wavelength
Therefore, putting given values into the above formula as follows.
E = 
=
=
or, =
m
= 428 nm
Thus, we can conclude that the maximum wavelength of light that can remove an electron from an atom on the surface of lithium metal is 428 nm.