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3 years ago

What is the difference between the endpoint and the equivalence point?

1 answer:

5 0

Endpoint . this is when the color of the indicator changes while equivalence is when added titrant is chemically equivalent completely to the analyte sample

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2 HCl + Na2SO4 > 2 NaCl + H2SO4

Cerrena [4.2K]

Answer:

Explanation:

8 0

3 years ago

Why are xrays used to probe the crystal structure of a material

ioda

Answer:

Because X-rays have wavelengths similar to the size of atoms

8 0

2 years ago

How many milliliters of 2.19 M H2SO4 are required to react with 4.75 g of solid containing 21.6 wt% Ba(NO3)2 if the reaction is

Setler [38]

Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% $Ba(NO_3)_2$ , thus,

Mass of $Ba(NO_3)_2$ = $\frac {21.6}{100}\times 4.75\ g$ = 1.026 g

Molar mass of $Ba(NO_3)_2$ = 261.337 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{1.026\ g}{261.337\ g/mol}$

$Moles= 0.003926\ mol$

Considering the reaction as:

$Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3$

1 moles of $Ba(NO_3)_2$ react with 1 mole of $H_2SO_4$

Thus,

0.003926 mole of $Ba(NO_3)_2$ react with 0.003926 mole of $H_2SO_4$

Moles of $H_2SO_4$ = 0.003926 mole

Also, considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Molarity = 2.19 M

So,

$2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}$

Volume = 0.0017927 L

Also, 1 L = 1000 mL

<u>So, volume = 1.7927 mL</u>

5 0

3 years ago

How many aluminum atoms are in 1 mole of aluminum?

natulia [17]

Answer:

2 atoms of aluminium makes a molecule of aluminium

8 0

3 years ago

Given the general chemical equation 3A + 2B → C + 5D,

Irina-Kira [14]

Answer :

(a) The number of moles of D produced can be, 6.67 moles.

(b) The volume of D prepared can be, 24.5 L

Explanation :

The given chemical reaction is:

$3A+2B\rightarrow C+5D$

Part (a) :

From the balanced chemical reaction, we conclude that:

As, 3 moles of A react to give 5 moles of D

So, 4 moles of A react to give $\frac{5}{3}\times 4=6.67$ moles of D

Thus, the number of moles of D produced can be, 6.67 moles.

Part (b) :

As we know that 1 moles of substance occupies 22.4 L volume of gas.

As, $2\times 22.4L$ volume of B gives $5\times 22.4L$ volume of D

As, 9.8 L volume of B gives $\frac{5\times 22.4L}{2\times 22.4L}\times 9.8L=24.5L$ volume of D

Thus, the volume of D prepared can be, 24.5 L

4 0

3 years ago