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Xelga [282]
3 years ago
14

What is the difference between the endpoint and the equivalence point?

Chemistry
1 answer:
True [87]3 years ago
5 0

Endpoint . this is when the color of the indicator changes  while  equivalence is when added titrant is chemically equivalent completely to the analyte sample  

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How many moles are equal to 1.3 x 1024 atoms of aluminum?
marshall27 [118]

Answer:

<h3>The answer is 2.16 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.3 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 2.159468...

We have the final answer as

<h3>2.16 moles</h3>

Hope this helps you

8 0
3 years ago
Why is a changing ocean temperature of only one or 2 degrees so concerning? Please help!!!!
Svetllana [295]
Because it throws the earth off balance and if it does it often enough then it will soon add up.

6 0
3 years ago
Read 2 more answers
Which of the following is a clue that something is pseudoscience?
adelina 88 [10]
D i think if not here’s this a collection of beliefs or practices mistakenly regarded as being based on scientific method
7 0
3 years ago
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
How many moles in 30.0 grams of h3po4
jok3333 [9.3K]
Molar mass H₃PO₄ = 98.0 g/mol

1 mole ----- 98.0 g
? mole ------ 30.0 g

moles = 30.0 * 1 / 98.0

= 0.306 moles

hope this helps!


5 0
3 years ago
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