<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
▬▬▬▬▬▬▬▬▬▬▬▬
The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
The distance ( S ) is represented by the equation:
S ( t ) = - 16 t² + 25
- 16 t² + 25 = 0
- 16 t² = - 25 / · ( - 1 )
16 t² = 25
t ² = 25 / 16
t = √( 25/16) = 5/4 = 1.25 s ( we will not accept the negative value )
Answer:
The acorn is moving trough the air for 1.25 seconds.
Answer:
The correct answer should be D.
Step-by-step explanation:
Answer:
Mean: 8,75
Median: 7,5
Step-by-step explanation:
To find Mean
To find the mean data you have to put data all set in order:
3, 4, 6, 6, 9, 12, 15, 15
Then, all of the numbers in the data set added together and then divided by how many numbers in the data that already put in order:
3 + 4 + 6 + 6 + 9 + 12 + 15 + 15 = 70
There are 8 numbers in the data so divide 70 by 8:
70 ÷ 8 = 8,75
----
To find Median
The median is in the middle number of the data that already in order. Which is number 6 and 9.
Median = (6 + 9) ÷ 2
Median = 15 : 2
Median = 7,5
