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yulyashka [42]
4 years ago
8

F(x) = 5(2)x

Mathematics
1 answer:
OlgaM077 [116]4 years ago
4 0
Krista's pattern will have the highest amount.

Here is were each person would be at the end of 5 days.

Anita:
5(2)^8 = 160

Juan:
3(3)^8 = 729

Krista:
8(3)^5 = 1944

To make an effective argument for your assignment, you should create tables for each person and show how they changed.
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Helpppppppppppp plss with this problem
3241004551 [841]

Given :7872 ÷ 305.

Because it's estimation. So, we need to estimate the number 7872 to 8000.

In order to divide 8000 by a number we need to estimate 305 to the 400. Because 400 is exact divisor of 8000.

If we divide 8000 by 400 we get 20.

And it's obviously less then 60000 ÷ 300= = 200.

20 < 200.

<h3>Therefore, Harrison is absolutely correct.</h3>
6 0
4 years ago
What does the product (-5-2i)(3+7i) equal
Marina CMI [18]
This in what I got:
(-7i)(10i)
-70i
8 0
3 years ago
I need help. ASAP!<br> Divide.<br><br><br> (3b^3 – 10b^2 + 4) ÷ (3b – 1)
viktelen [127]

Step-by-step explanation:

try surfing how to divide a function by the long division method

3 0
3 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
A room measures 12 feet by 16 feet long. what is the square footage of this room
Leno4ka [110]
12 x 16 = 192. So, the room is 192 square feet.
7 0
3 years ago
Read 2 more answers
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