Answer:
.
Explanation:
-Synthesis reactions are reactions that appear when two distinct atoms or molecules engage to structure a specific molecule or compound. Most of the time, when a synthesis response occurs, electricity is launched and the response is exothermic. However, an endothermic consequence is additionally possible.
-A decomposition response starts offevolved from a single substance and produces extra than one substance; that is, it decomposes. One substance as a reactant and greater than one substance as the merchandise is the key attribute of a decomposition reaction. For example, in the decomposition of sodium hydrogen carbonate (also recognized as sodium bicarbonate)
-A single-replacement response (sometimes referred to as a single-displacement reaction) is a chemical response in which one aspect is substituted for every other factor in a compound, producing a new aspect and a new compound as merchandise
-A double-replacement response (sometimes referred to as a double-displacement reaction) takes place when components of two ionic compounds are exchanged, making two new compounds. A attribute of a double-replacement equation is that there are two compounds as reactants and two distinctive compounds as product
-A combustion response happens when a reactant combines with oxygen, many instances from the atmosphere, to produce oxides of all different factors as products; any nitrogen in the reactant is transformed to elemental nitrogen, N2. Many reactants, referred to as fuels, incorporate normally carbon and hydrogen atoms, reacting with oxygen to produce CO2 and H2O
The researcher may first weight the beaker with water and then start to heat the water to a constant temperature, for example 30 °C and then start adding salt and stirring. He should add salt slowly until solid salt starts to become visible and the solution starts becoming cloudy. When this happens, he should quickly weigh the beaker. The increase in mass is the mass of salt dissolved at that temperature.
The procedure is then repeated but at an increased temperature until 5-6 temperatures have been tested.
You would do M divided by V= D and the answer is 0.0284
Answer: [N2]₀ = 10M and [H2]₀ = 11M
Explanation: To calculate the initial concentration, you would have to set up an ICE table, which is an organized way of tracking known quantities or the ones you want to find. ICE stands for:
I is initial amount;
C is change in concentration;
E is for equilibrium concentration;
For the mixture,
N2 3H2 2NH3
I [N2]₀ [H2]₀ 0
C - x -3x +2x
E [N2]₀ - x =8 [H2]₀ - 3x =5 2x =4
With the product, we can find "x":
2x=4
x=2M
With x=2, find the concentrations:
[N2]₀ - x = 8
[N2]₀ = 10M
[H2]₀ - 3x = 5
[H2]₀ = 11M
The initial concentrations of nitrogen gas [N2] is 10.0 M and of hydrogen gas [H2] is 11.0 M.
NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions.
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
pH + pOH = 14
Since pH = 11.50
pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 3.2 x 10⁻³ M
therefore [NaOH] = 3.2 x 10⁻³ M
