Answer:
0.25 mol
Explanation:
Use the formula n=N/NA
n= number of mols
N = number of particles
Nᵃ = Avogadros constant = 6.02 x 
So, n= 
The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.
Hope this helped :)
Answer:
0.908 L.
Explanation:
- Firstly, we should calculate the number of moles of 1.60 g argon.
- n of Ar = mass / molar mass of Ar = (1.60 g) / (39.948 g/mol) = 0.04 mol.
- |t is established and known that the molar volume of a gas at STP (Standard Temperature and Pressure) is equal to 22.4 L for 1 mole of any ideal gas at a temperature of 273.15 K and a pressure of 1.00 atm.
<u><em>using cross multiplication:</em></u>
1.0 mole of Ar gas will occupy → 22.7 L
0.04 mole of Ar gas will occupy → ??? L
∴ The volume occupied by Ar = (0.04 mole) (22.7 L) / (1.0 mole) = 0.908 L.
Answer: H2O
Explanation: The given balanced chemical reaction is,
This reaction is a reversible reaction.
The rate of forward reaction will be,
The rate of backward reaction will be,
And at equilibrium the rate of reaction is equal to the rate of backward reaction divided by the rate of forward reaction.
