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Vitek1552 [10]
3 years ago
15

Can some one help please i’m in danger !

Physics
1 answer:
Kitty [74]3 years ago
4 0
<h3>Formula:</h3>

Distance = Speed × Time

<h2>Answer:</h2><h3>Level 1:</h3>

The distance travelled during 5 hours = 0 × 5 = <u>0 km</u>

<h3>Level 2:</h3>

The distance travelled during 5 hours = 50 × 5 = <u>2</u><u>5</u><u>0</u><u> </u><u>km</u>

<h3>Level 3:</h3>

The distance travelled during 5 hours = 60 × 5 = <u>3</u><u>0</u><u>0</u><u> </u><u>km</u>

<h3>Level 4:</h3>

The distance travelled during 5 hours = 60 × 4 = <u>2</u><u>4</u><u>0</u><u> </u><u>km</u>

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4 years ago
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A giant wall clock with diameter d rests vertically on the floor. The minute hand sticks out from the face of the clock, and its
Katyanochek1 [597]

Answer:

d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)

Explanation:

We can try writing the equation of the horizontal component of the length of the minute hand in terms of distance and the angle, that depends of time in this particular case.

The x-component of the length of the minute hand is:

d_{x}(t)=dcos(\theta (t)) (1)

  • d is the length of the minute hand (d=D/2)
  • D is the diameter of the clock
  • t is the time (min)

Now, using the angular kinematic equations we can express the angle in term of angular velocity and time. As we know, the minute hand moves with a constant angular velocity, so we can use this equation:

\theta (t)=\omega *t (2)

Also we know, that the minute hand moves 90 degrees or π/2 rad in 15 min, so using the definition of angular velocity, we have:

\omega=\frac{\Delta \theta}{\Delta t}=\frac{\theta_{f}-\theta_{i}}{t_{f}-t{i}}=\frac{\pi/2-0}{15-0}=\frac{\pi}{30}

Now, let's put this value on (2)

\theta (t)=\frac{\pi}{30}*t

Finally the length x(t) of the shadow of the minute hand as a function of time t, will be:

d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)

I hope it helps you!

6 0
3 years ago
An element with only neutrons?
nirvana33 [79]
All except for one tom of the element with different number of neutron
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4 years ago
if you dilute green tea 9.0, alkaline water 8.0, fruit juice 6.8, vinegar 3.5, and gatorade 3.0 which substance will have a high
tensa zangetsu [6.8K]

Answer:

green tea

Explanation:

According to the question

It is mentioned that

dilute green tea 9.0,

alkaline water 8.0,

fruit juice 6.8,

vinegar 3.5,

and Gatorade 3.0

Now based on the above information

As it can bee seen that the Dilute green tea contains higher pH as compared with the others

So, the substance that have a bigger or higher pH is green tea

8 0
3 years ago
Urgent! please help!
kap26 [50]

_{94}^{239}Pu+ _{0}^{1}n--->_{40}^{100}Zr+_{x}^{y}Element+2_{0}^{1}n\\ \\ 94+0=40+x+0, x= 54,\\ \\ 239+1 = 100+y+2*1, y=138\\ \\_{54}^{138}Element= _{54}^{138}Xe

Answer is A.

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